Created by Martha Stefany
over 9 years ago
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Senθcscθ=1tanθcotθ=1Cosθsecθ=1csc θ=1/senθcotθ =1/tanθ tanθ =1/cotθ cosθ=1/secθ secθ=1/cosθ tanθ=senθ/cosθcotθ=cosθ/senθidentidades pitagóricassen ² θ + cos ² θ=1sen ² θ= 1 - cos ² θ cos ² θ = 1 - sen ² θ sec ² θ = tg ² θ + 1tg ² θ = sec ² θ -1 ctg ² θ= csc ² θ -1 csc ² θ= ctg ² θ + 1
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