Zusammenfassung der Ressource
Pelota de ping pong
- informacion
- Pa = 1000 kg/m3
g = 9.8 m/s2, D=
3.8 cm r = 38/2
cm = 1.9 cm =
0.019 m
- Pp = 0.084 g/cm3
= 84 kg/m3
- ecuaciones
- Fb= Wp + Fa
Wp= m* g =
pp*Vp*g
- va= agua desplazada
vp = volumne de la
pelota
- va = vp
- VP =4\3 * π*r3
- realizamos
- Fb = vp*pa*g
- Wp= peso de la pelota
- Wp=pp*Vp*g
- Fa = Fb - Wp