The Electrolysis of Solutions

Quiz von Joanna van Dyk, erstellt am more than 1 year ago

GCSE Chemistry (Reactivity Series, Metal Extraction and Electrolysis) Quiz am The Electrolysis of Solutions, erstellt von Joanna van Dyk am 26/12/2015.

	Erstellt von Joanna van Dyk vor fast 9 Jahre

Schließen

GCSE Chemistry (Reactivity Series, Metal Extraction and Electrolysis) Quiz am The Electrolysis of Solutions, erstellt von Joanna van Dyk am 26/12/2015.

The Electrolysis of Solutions

Frage 1 von 9

Wähle von der Dropdown-Liste, um den Text zu vervollständigen.

In a mixture of ions it is the ion which is ( lower, higher ) in the reactivity series that will be discharged and gain electrons (i.e. is ( reduced, oxidised, thrown out of the window ))

Erklärung

Frage 2 von 9

Wähle von der Dropdown-Liste, um den Text zu vervollständigen.

So as ( hydrogen, sodium ) is lower than ( sodium, hydrogen ) in the reactivity series it is the ( H+, Na + ) ion which is discharged and so the element ( H2, Na ) will be formed.

Erklärung

Frage 3 von 9

Fülle die Lücken, um den Text zu vervollständigen.

The half equation for this is:

+ =

Erklärung

Frage 4 von 9

Fülle die Lücken, um den Text zu vervollständigen.

At the anode is made unless a ion is present, in which case the is made.

Erklärung

Frage 5 von 9

Fülle die Lücken, um den Text zu vervollständigen.

Write the half equation for the formation of oxygen (from hydroxide ions) at the anode:

= 2 + 2 + -

Erklärung

Frage 6 von 9

What will be produced at the Cathode in the electrolysis of a potassium sulphate solution?

Wähle eine der folgenden:

Erklärung

Frage 7 von 9

What will be produced at the anode in the electrolysis of a potassium sulphate solution?

Wähle eine der folgenden:

Erklärung

Frage 8 von 9

What will be produced at the cathode in the electrolysis of a Magnesium Bromide solution?

Wähle eine der folgenden:

Erklärung

Frage 9 von 9

What will be produced at the anode in the electrolysis of a Magnesium Bromide solution?

Wähle eine der folgenden:

Erklärung

GCSE Chemistry (Reactivity Series, Metal Extraction and Electrolysis) Quiz am The Electrolysis of Solutions, erstellt von Joanna van Dyk am 26/12/2015.

The Electrolysis of Solutions

Frage 1 von 9

Wähle von der Dropdown-Liste, um den Text zu vervollständigen.

In a mixture of ions it is the ion which is lower higher( lower, higher ) in the reactivity series that will be discharged and gain electrons (i.e. is reduced oxidised thrown out of the window( reduced, oxidised, thrown out of the window ))

Erklärung

Frage 2 von 9

Wähle von der Dropdown-Liste, um den Text zu vervollständigen.

So as hydrogen sodium( hydrogen, sodium ) is lower than sodium hydrogen( sodium, hydrogen ) in the reactivity series it is the H+ Na +( H+, Na + ) ion which is discharged and so the element H2 Na( H2, Na ) will be formed.

Erklärung

Frage 3 von 9

Fülle die Lücken, um den Text zu vervollständigen.

The half equation for this is: + =

Erklärung

Frage 4 von 9

Fülle die Lücken, um den Text zu vervollständigen.

At the anode is made unless a ion is present, in which case the is made.

Erklärung

Frage 5 von 9

Fülle die Lücken, um den Text zu vervollständigen.

Write the half equation for the formation of oxygen (from hydroxide ions) at the anode: = 2 + 2 + -

Erklärung

Frage 6 von 9

What will be produced at the Cathode in the electrolysis of a potassium sulphate solution?

Wähle eine der folgenden:

Erklärung

Frage 7 von 9

What will be produced at the anode in the electrolysis of a potassium sulphate solution?

Wähle eine der folgenden:

Erklärung

Frage 8 von 9

What will be produced at the cathode in the electrolysis of a Magnesium Bromide solution?

Wähle eine der folgenden:

Erklärung

Frage 9 von 9

What will be produced at the anode in the electrolysis of a Magnesium Bromide solution?

Wähle eine der folgenden:

Erklärung

In a mixture of ions it is the ion which is ( lower, higher ) in the reactivity series that will be discharged and gain electrons (i.e. is ( reduced, oxidised, thrown out of the window ))

So as ( hydrogen, sodium ) is lower than ( sodium, hydrogen ) in the reactivity series it is the ( H+, Na + ) ion which is discharged and so the element ( H2, Na ) will be formed.

The half equation for this is:

+ =

Write the half equation for the formation of oxygen (from hydroxide ions) at the anode:

= 2 + 2 + -