If y = x^2 + 3x + 2 dy/dx= x +
If asked to differentiate y= (x+3)^2, I would use the rule
If asked to differentiate y= (x+1)/(x^2 - 2), I would use the rule
The gradient of a tangent is 1/3. The gradient of its normal is
If f(x) = X^2 + 2x + 1, the value of x, dy/dx = x+. This means the gradient of the curve is 0 when x =
y = ln(3x^2) y= ln + lnx dy/dx =
y = sin 3x dy/dx =
f(x) = tan2x f'(x) = sec^2()
f(x) = 3x^2-x^3 f'(x) = 6x-3x^2 Stationary points are at values of x for which f'(x) = 0, (x = 0 or x = ) f''(x) = - x When x=0, stationary point is a because at x=0, f''(x) is positive.
The second derivative of a function is also known as dy^2/dx^2
