Zusammenfassung der Ressource
Frage 1
Antworten
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a ≤ x ≤ b
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{x ∈ R : a ≤ x ≤ b }
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{x ∈ R : a < x < b }
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a < x < b
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(4,1)
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What are sets with curved brackets named?
Antworten
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Open Intervals
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Closed Intervals
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What are sets with square brackets named?
Antworten
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Closed Intervals
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Open Intervals
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State the triangle inequality
Antworten
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|a + b| ≤ |a| + |b|
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a + b ≤ |a| + |b|.
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|a + b| < |a| + |b|
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|a + b| ≤ |a| - |b|.
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Define what is meant by a sequence
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Corresponds to a mapping (or ) from the natural numbers N to the real numbers R.
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Ordered list
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Numbers in a set
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corresponds to a mapping (or ) from a number to another
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corresponds to a mapping (or ) from the real numbers R to the real numbers N.
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Corresponds to a mapping (or ) from the natural numbers N to the integers Z.
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An increasing list of values mapped from the Natural numbers N to the integers Z
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Define tends to infinity
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A sequence (an) of real numbers tends to infinity if given any real number A > 0 there exists N ∈ N such that an>A for all n>N.
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It gets bigger and bigger past a number
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A sequence (an) of numbers tends to infinity if given any number A > 0 there exists N ∈ N such that an>A for all n>N.
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A sequence (an) of real numbers goes to infinity if given any real number A > 0 there exists N ∈ N such that an>A for all A>N.
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A sequence (an) of real numbers tends to infinity if given any real number A > 0 there exists N ∈ N such that an>A for some A>N.
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A sequence (an) of real numbers tends to infinity if given any real number A > 0 there exists z ∈ Z such that an>A for all A>N.
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Define Tends to infinity
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∀A>0 ∃N∈N s.t. an>A ∀n>N
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∃A>0 ∃N∈N s.t. an>A ∀n>N
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∀A>0 ∀N∈N s.t. anN
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∀A>0 ∃N∈N s.t. an>A ∀n<N
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What is |x|^2 equal to ?
Frage 9
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What's another way to write √(x^2)
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Define Convergent sequence
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A sequence (an) of real numbers converges to a real
number ℓ if given any e > 0 there exists N ∈ N such that
|an − ℓ| < e for all n > N
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A sequence (an) of numbers converges to a real
number ℓ if given any e > 0 there exists N ∈ N such that
|an − ℓ| < e for all n > N
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A sequence (an) of real numbers converges to a
number ℓ if given any e > 0 there exists N ∈ N such that
|an − ℓ| < e for all n > N
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A sequence (an) of real numbers converges to a real
number ℓ if given any e < 0 there exists N ∈ N such that
|an − ℓ| < e for all n > N
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A sequence (an) of real numbers converges to a real
number ℓ if given any e > 0 there exists Z ∈ N such that
|an − ℓ| < e for all n > N
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A sequence (an) of real numbers converges to a real
number ℓ if given any e > 0 there exists N ∈ N such that
|an − ℓ| < e for some n > N
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A sequence (an) of real numbers converges to a real
number ℓ if given any e > 0 there exists N ∈ N such that
|e − ℓ| < e for all n > N
Frage 12
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(Converging series) If |an-l| = 1/n. What should you let N be greater than?
Frage 13
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Define bounded above
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if there exists some M ∈ R such that an ≤ M for all n ∈ N
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if there exists some M ∈ N such that an ≤ M for all n ∈ N
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if there exists some M ∈ R such that an ≤ R for all n ∈ N
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if there exists some M ∈ R such that an ≤ M for some n ∈ N
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if there exists some M ∈ R such that an ≤ M for all R ∈ N
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Define bounded below
Antworten
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there exists some M ∈ R such that an ≥ M for all n ∈ N.
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there exists some M ∈ R such that an < M for all n ∈ N.
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there exists some M ∈ N such that an < M for all n ∈ N.
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there exists some M ∈ N such that an ≥ M for all n ∈ N.
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there exists some M ∈ R such that an ≥ M for some n ∈ N.
Frage 15
Antworten
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there exist M1, M2 ∈ R such that M1 ≤ an ≤ M2 for all n ∈ N.
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there exist M1, M2 ∈ R such that M1 ≤ an ≤ M2 for some n ∈ N.
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there exist M1, M2 ∈ N such that M1 ≤ an ≤ M2 for all n ∈ N.
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there exist M1, M2 ∈ Q such that M1 ≤ an ≤ M2 for all n ∈ N.
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there exist M1, M2 ∈ R such that M1 < an < M2 for all n ∈ N.
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there exist M1, M2 ∈ R such that M1 ≤ an < M2 for all n ∈ N.
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Give a sequence that is bounded but does not converge
an = [blank_start](-1)^n[blank_end]
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Lemma 1.9, Convergent sequences are bounded. Every [blank_start]convergent[blank_end] sequence of [blank_start]real[blank_end] numbers is a [blank_start]bounded[blank_end] sequence
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AOL: lim an = ℓ and lim bn = m
Then,
lim(an + bn) = ?
Antworten
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ℓ + m,
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ℓm,
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ℓ - m
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ℓ + m - e
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AOL: lim an = ℓ
Then,
lim λan = ?
Frage 20
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AOL: lim an = ℓ and lim bn = m
Then,
lim anbn = ?
Frage 21
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Sandwich Theorem/Squeeze Rule
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. Let N ∈ N and ℓ ∈ R. Suppose (an), (bn)
and (cn) are sequences satisfying
an ≤ bn ≤ cn for all n ≥ N.
If an → ℓ and cn → ℓ, then bn → ℓ.
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. Let N ∈ N and ℓ ∈ R. Suppose (an), (bn)
and (cn) are sequences satisfying
an ≤ n ≤ cn for all n ≥ N.
If an → ℓ and cn → ℓ, then bn → ℓ.
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. Let N ∈ R and ℓ ∈ N. Suppose (an), (bn)
and (cn) are sequences satisfying
an ≤ bn ≤ cn for all n ≥ N.
If an → ℓ and cn → ℓ, then bn → ℓ.
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. Let N ∈ N and ℓ ∈ R. Suppose (an), (bn)
and (cn) are sequences satisfying
an ≤ bn ≤ cn for some n ≥ N.
If an → ℓ and cn → ℓ, then bn → ℓ.
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If |λ| < 1 then λ^n
n → ?
as n → ∞
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s>0
1/(n^s) → ?
as n → ∞.
Frage 24
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(n^s)/ n! → ?
as n → ∞
Frage 25
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(λ^n)/n! → ?
as n → ∞.