Zusammenfassung der Ressource
Frage 1
Frage
Formula for Raw
([blank_start]Mouth[blank_end] Pressure - [blank_start]Alveolar[blank_end] Pressure) / [blank_start]Flow[blank_end]
Frage 2
Frage
Airway resistance:
Difference in pressure between the [blank_start]mouth[blank_end] and the [blank_start]alveoli[blank_end], related to gas [blank_start]flow[blank_end] at the mouth.
Typical value [blank_start].6[blank_end] - [blank_start]2.4[blank_end] cmH2O / L/sec
Measured by body pleth: Pt pants gently with open shutter at a rate of [blank_start]1.5[blank_end] - [blank_start]2.5[blank_end] breaths per second. This creates an 2 shaped curve on screen that plots flow against box pressure. Shutter closes and second curve is produced that plots mouth pressure against box pressure. Raw is calculated from these 2 graphs.
Antworten
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mouth
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alveoli
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flow
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.6
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2.4
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1.5
-
2.5
Frage 3
Frage
Normal Raw Values
Nose, mouth, upper airway: [blank_start]50[blank_end]%
Trachea, Bronchi: [blank_start]30[blank_end]%
Small Airways: [blank_start]20[blank_end]%
Frage 4
Frage
Airway Conductance ([blank_start]Gaw[blank_end])
Flow per unit of [blank_start]pressure[blank_end] change in L/sec/cmH2O
Reciprical of Raw: 1/[blank_start]Raw[blank_end]
[blank_start]Specific[blank_end] conductance is the same but is measured by liter of [blank_start]lung[blank_end] volume: (1/Raw)/[blank_start]TLC[blank_end] or [blank_start]FRC[blank_end]
Normal Value: .[blank_start]42[blank_end] - [blank_start]1.67[blank_end] L/sec/cmH20
More appropriate than Raw for small airway disease
Antworten
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Gaw
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pressure
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Raw
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Specific
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lung
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TLC
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FRC
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42
-
1.67
Frage 5
Frage
Compliance
Volume Change per unit of Pressure change
CLT = Lungs and [blank_start]Thorax[blank_end] = [blank_start].2[blank_end] L/cmH2O
CL = [blank_start]Lungs[blank_end] Only = [blank_start].2[blank_end] L/cmH2O
CT = [blank_start]Thorax[blank_end] only = [blank_start].1[blank_end] L/cmH2O
In vented patients record plateau pressure at different lung volumes.
Antworten
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.2
-
.2
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Thorax
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Lungs
-
.1
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Thorax
Frage 6
Frage
Compliance:
[blank_start]Esophogeal[blank_end] Balloon Technique
Catheter with inflatable [blank_start]balloon[blank_end] is marked [blank_start]50[blank_end] cm from the tip.
Balloon is inserted through the nose and swallowed into [blank_start]stomach[blank_end].
In the stomach pressure swings [blank_start]positive[blank_end] on inspiration and [blank_start]negative[blank_end] on expiration after 1 ml of air is injected.
Balloon is retracted into [blank_start]esophagus[blank_end] and the pressure swings [blank_start]reverse[blank_end].
Catheter is [blank_start]35[blank_end] - [blank_start]45[blank_end] cm from the nose.
Air is evacuated from the balloon, then [blank_start].5[blank_end] ml is injected.
Pt inspires to [blank_start]TLC[blank_end] before taking any measurements to standardize.
Have pt inspire again - pressure and volume measurements are taking at zero flow.
Lung compliance is taken from slope of P-V [blank_start]curve[blank_end] over segment from FRC to [blank_start]FRC[blank_end] +.5L
At FRC balloon pressure should equal [blank_start]-5[blank_end] cmhO
Max elastic [blank_start]recoil[blank_end] pressure is the most [blank_start]negative[blank_end] pressure at TLC
Static lung compliance is the difference of [blank_start]esophageal[blank_end] pressure and mouth [blank_start]pressure[blank_end].
Antworten
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Esophogeal
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balloon
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50
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stomach
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positive
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negative
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esophagus
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reverse
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35
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45
-
.5
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TLC
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FRC
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curve
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-5
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recoil
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negative
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pressure
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esophageal
Frage 7
Frage
Static Lung Compliance
Change in lung [blank_start]volume[blank_end] per unit change in transpulmonary [blank_start]pressure[blank_end] measured over the straight portion of P-V curve between FRC and FRC + [blank_start].5L[blank_end]
Δ[blank_start]V[blank_end] / Δ[blank_start]Pst[blank_end]
Normal Value = [blank_start].2[blank_end] L/cmH2O
Antworten
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volume
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pressure
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.5L
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Pst
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V
-
.2
Frage 8
Frage
Abnormal Compliance
CL is [blank_start]decreased[blank_end] in [blank_start]restrictive[blank_end] disease like pneumonia, atelectasis, pulm fibrosis
CL is [blank_start]increased[blank_end] in emphysema because of loss of [blank_start]elasticity[blank_end]
CT is [blank_start]decreased[blank_end] with chest wall deformities and obesity.
Antworten
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restrictive
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elasticity
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decreased
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increased
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decreased
Frage 9
Frage
Maximum Static Recoil Pressure
Most [blank_start]negative[blank_end] pressure obtained at TLC
Normal value is [blank_start]24.4[blank_end] - [blank_start]34.5[blank_end] cmH2O
Frage 10
Frage
CoEffecient of Retraction
COR is used to express the maximal static recoil [blank_start]pressure[blank_end] of the lung relative to the lung [blank_start]volume[blank_end] (TLC)
COR = (Pst at [blank_start]TLC[blank_end]) / [blank_start]TLC[blank_end]
Normal Value = [blank_start]4[blank_end]-[blank_start]8[blank_end] cmH2O/L
Antworten
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pressure
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volume
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TLC
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TLC
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4
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8