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Dynamic Equilibrium: A situation in which the [blank_start]composition[blank_end] of a constant [blank_start]concentration[blank_end] reaction mixture does not [blank_start]change[blank_end] because both forward and backward reactions are proceeding at the same [blank_start]rate[blank_end].
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composition
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concentration
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rate
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change
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Which of the following are conditions which apply to all equilibria?
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Equilibrium can only be reached in a closed system.
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Equilibrium can only be reached if the reaction starts from the reactants on the left of the equation.
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Equilibrium is a dynamic process which is reached when the rates of two opposing simultaneous processes are the same.
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Equilibrium has been reached when the amounts of products and reactants in the equilibrium mixture is the same.
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You can tell that equilibrium has been reached when the macroscopic properties of the system do not change with time (i.e. density, concentration, colour and pressure)
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Once equilibrium is reached the concentrations of the reactants and the products do not change.
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What can be said about the rates of the forwards and backwards reactions when equilibrium has been reached?
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A + B <---> C + D
At the [blank_start]start[blank_end] of the reaction the forward rate is fast, because A and B are [blank_start]plentiful[blank_end]. There is no [blank_start]reverse reaction[blank_end] because there is no C and D.
Then as the [blank_start]concentrations[blank_end] of C and D build up, the reverse reaction speeds up. At the same time the concentrations of A and B [blank_start]decrease[blank_end] so the forward reaction [blank_start]slows down[blank_end].
A point is reached where exactly the same [blank_start]number of particles[blank_end] are changing from A and B to C and D as are changing from C and D to A and B. [blank_start]Equilibrium[blank_end] has been reached.
NB. An equilibrium [blank_start]mixture[blank_end] can have any proportions of reactants and products. The proportions may be changed depending on the [blank_start]conditions[blank_end] of the reaction, such as temperature, [blank_start]pressure[blank_end], and concentration. But at any given constant conditions the proportions of reactants and products [blank_start]do not[blank_end] change.
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start
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plentiful
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reverse reaction
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concentrations
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decrease
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slows down
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number of particles
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Equilibrium
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mixture
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conditions
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pressure
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do not
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Le Chatelier's Principle: For a closed system in dynamic equilibrium, if a change is made the equilibrium will shift to increase that change.
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If you [blank_start]increase[blank_end] the concentration of one of the reactants, Le Chatelier's principle says that the [blank_start]equilibrium[blank_end] will shift in the direction what tends to reduce the concentration of this reactant.
A(aq) + B(aq) <---> C(aq) + D(aq)
If you add some extra A (increase its [blank_start]concentration[blank_end]), the only way that the system can reduce the concentration of A is by [blank_start]reacting[blank_end] it with B to form more C and D. So, adding more A uses up more B, [blank_start]produces[blank_end] more C and D, and moves the equilibrium to the [blank_start]right[blank_end]. You end up with a [blank_start]greater[blank_end] proportion of products in the reaction mixture than before.
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increase
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concentration
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reacting
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produces
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right
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greater
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equilibrium
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Pressure changes only affect reactions involving [blank_start]gases[blank_end]. Changing the overall pressure will only change the position of equilibrium of a gaseous reaction if there are a [blank_start]different[blank_end] number of molecules on either side of the equation.
N204(g) <---> 2NO2
[blank_start]Increasing[blank_end] the pressure of a gas means that there are more molecules of it in a given volume - it is equivalent to increasing the [blank_start]concentration[blank_end] of a solution.
If you increase the pressure on this system, Le Chatelier's principle tells us that the position of equilibrium will move to [blank_start]decrease[blank_end] the pressure. This meas it will more to the [blank_start]left[blank_end] because fewer molecules exert less pressure.
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gases
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different
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Increasing
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concentration
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decrease
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left
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Increasing the pressure or decreasing the volume of a mixture of gases decreases the concentration of all the reactants and products by the same amount, not just one of them.
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The rate at which equilibrium is reached will be speeded up by increasing the pressure, as there will be more collisions in a given time.
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Increasing the temperature of a reaction will cause the equilibrium to shift in which direction?
Frage 12
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What effect would adding a catalyst have on a reversible reaction in a closed system? (Choose TWO)
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The position of equilibrium would shift to favour the forwards reaction.
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The position of equilibrium would shift to favour the reverse reaction.
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The position of equilibrium would not change.
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Equilibrium would be reached faster.
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The reaction would never reach equilibrium.
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80% of ammonia produced is used to make which product?
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Fertilisers
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Synthetic fibers
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Dyes
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Explosives
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Plastics
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N2(g) + [blank_start]3[blank_end]H2(g) <---> [blank_start]2[blank_end]NH3(g) [delta H = -92kJmol^-1]
Almost all ammonia is made by the [blank_start]Haber[blank_end] process, in which the reaction above is the key step. A low temperature and high [blank_start]pressure[blank_end] would give close to 100% conversion whereas low pressure and high temperature would give almost no [blank_start]ammonia[blank_end]. However, a compromise is used to ensure the rate of reaction is [blank_start]economically[blank_end] viable and the conditions safe. Most plants run at a pressure of around 20000kPa (c. [blank_start]200[blank_end] atmospheres) and a temperature of about [blank_start]670[blank_end]K (c. 450 celsius).
The raw materials for the Haber process are air (providing the nitrogen), water, and natural gas (methane). These provide the hydrogen by the following reaction:
[blank_start]CH4[blank_end](g) + H2O(g) ---> [blank_start]CO[blank_end](g) + 3H2(g)
The nitrogen and hydrogen are fed into a converter in the ratio [blank_start]1:3[blank_end] and passed over an [blank_start]iron[blank_end] catalyst.
The conversion is not at maximum as the conditions are not optimum (a [blank_start]compromise[blank_end] is used) and the gases flow continuously over the catalyst so they do not spend long enough in contact with the catalyst to reach [blank_start]equilibrium[blank_end]. Any unconverted reactants are [blank_start]recycled[blank_end] through the converter to increase the yield.
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3
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2
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Haber
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pressure
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ammonia
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200
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670
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economically
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CH4
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CO
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1:3
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iron
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compromise
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equilibrium
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recycled
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The most common source of ethanol for industrial use is the fermentation of sugars such as glucose.
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Ethanol is the alcohol in alcoholic drinks, but also has many [blank_start]industrial[blank_end] uses for example making cosmetics, drugs, detergents, inks, and as a motor [blank_start]fuel[blank_end]. At present the main source of ethanol for industrial use is [blank_start]ethene[blank_end] from crude oil.
Ethanol is made by the hydration of ethene. The reaction is [blank_start]reversible[blank_end] and is speeded up by a catalyst of [blank_start]phosphoric[blank_end] acid absorbed on silica.
The equation is:
C2H4(g) + [blank_start]H2O[blank_end](g) <---> C2H5OH(g) [delta H = -46kJmol^-1]
Applying Le Chatelier's principle to this predicts the maximum yield will be produced with [blank_start]high[blank_end] pressure, low temperature, and excess steam. However, there are practical problems: high pressure can cause ethene to polymerise; high pressure increases [blank_start]costs[blank_end] and danger; low temperature reduces the rate of reaction; too much steam dilutes the catalyst. Therefore in practise, conditions of about 570K and [blank_start]6500[blank_end]kPa are used. These give a conversion to ethanol of only around 5%, but the unreacted reactants are [blank_start]recycled[blank_end] until about 95% conversion is obtained.
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industrial
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fuel
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ethene
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reversible
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phosphoric
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H2O
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high
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costs
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recycled
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6500
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Le Chatelier's principle tells us that the methanol synthesis reaction will give the highest yield at low temperature and high pressure.
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Which of the following is true?
The Kc of a reaction is...
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Kc > 1 --> [blank_start]equilibrium lies towards the products[blank_end]
Kc = 1 --> [blank_start]equal concentrations[blank_end]
Kc < 1 --> [blank_start]equilibrium lies towards the reactants[blank_end]
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The equilibrium constant (Kc) does not change with concentration or pressure, but it does when the temperature is changed.
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When can the number of moles of products and reactants be used to calculate the Kc instead of the concentrations?
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When all the products and reactants have different powers/indicies.
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When there is only one product.
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When all the products and reactants have equal volume.
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The Kc of the reaction between nitrogen monoxide (NO) and oxygen (O2) to form nitrogen dioxide (NO2) has no units.