MAS114 Revison Cards

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Revision Cards for MAS114 - University of Sheffield's Mathematics level 1 course.
Tom Tonner
Karteikarten von Tom Tonner, aktualisiert more than 1 year ago
Tom Tonner
Erstellt von Tom Tonner vor mehr als 6 Jahre
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Russell's Paradox: Prove that the set of all sets which are not elements of themselves is self-contradictory: If S∈S then by definition of S S∉S. If S∉S, then by definition of S S∈S.
Two functions are equal if: -Same domain and co-domain -For all a∈A, we have f(a)=g(a)
-Negation of A: -Contra-positive of A⇒B: ¬A ¬A ⇒ ¬B
Equivalence of: ¬(∀x ∈ X, P(x)) ¬(∃x ∈ X s.t P(x)) ∃x ∈ X s.t ¬P(x) ∀x ∈ X, ¬P(x)
Euclid's Theorem There are infinitely many prime numbers.
Definitions: -Greatest common divisor: -Least common multiple: -Co-prime: -gcd(a,b) is the largest positive integer which is a divisor of both a and b. -lcm(a,b) is the smallest positive integer which is a multiple of both a and b. -Two integers a and b are said to be co-prime if the gcd(a,b) = 1.
gcd properties: gcd(a,b) = gcd(b,a) gcd(a,0) = gcd(a,a) = a gcd(a,1) = 1 gcd(a,b) = gcd(a,-b) gcd(a,b) = gcd(a + kb, b)
a ≡ b (mod m) m | (a-b)
Congruence properties: - a ≡ a (mod m) - a ≡ b (mod m) ⇒ b ≡ a (mod m) - a ≡ b & b ≡ c ⇒ a ≡ c (mod m) - a ≡ b & c ≡ d ⇒ a+c ≡ b+d & a-c ≡ b-d & ac ≡ bd (mod m)
Fermat's little theorem a^(p-1)≡1 (mod m)
Fermat-Euler Theorem Let a, n be integers w/ gcd(a,n)=1 a^φ(n)≡1 (mod n). Where φ(n) is the number of integers between 1 to n which are co-prime to n
Wilson's Theorem (n-1)! ≡1 (mod m) iff n is prime
x is irrational y is rational Then: x+y is irrational xy is irrational (if y≠0)
Convergence definition: A sequence a_i converges to x if: ∀ε>0, ∃N∈N s.t. ∀n>N, |a_n - x|<ε
The four group axioms: G1 (Closure): ab∈G G2 (Associativity): (ab)c = a(bc) G3 (Neutral Element): ∃e s.t eg = g = ge G4 (Inverse): gh = e = hg
Albanian Group ab = ba
(gh)^-1 h^-1g^-1
Homomorphism: Isomorphism: f(xy) = f(x)f(y) Isomorphism is a bijective Homomorphism
Subgroup Criteria SG1: H ≠ ∅ SG2: gh∈H SG3: h^-1∈H
Group Actions GA1: e*x =x GA2: g(hx) = (gh)x
Orbit Counting Theorem n = 1/|G|*∑ |fix(g)|
Equivalence relations Reflexivity: a~a for all a Symmetry: if a~b then b~a for all a,b Transitivity: a~b and b~c then a~c
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