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Frage	Antworten
\(\frac{2}{3}\) =>	\ ( \ frac {2} {3} \ )
3\(\frac{1}{2}\) =>	3 \ ( \ frac {1} {2} \ )
\(\frac{2}{3} + \frac{3}{5}\ – \frac{3}{4}\) = = \(\frac{2·5·4+3·3·4–3·3·5}{3·5·4}\) = = \(\frac{40+36–45}{60}\) = \(\frac{31}{60}\)	\ ( \ frac {2} {3} + \ frac {3} {5} \ – \ frac {3} {4} \ ) = = \ ( \ frac {2·5·4+3·3·4–3·3·5} {3·5·4} \ ) = = \ ( \ frac {40+36–45} {60} \ ) = \ ( \ frac {31} {60} \ )
\(\frac{2}{3}\)x\(\frac{3}{5}\) =>	\ ( \ frac {2} {3} \ ) x \ ( \ frac {3} {5} \ )
\(\frac{2}{3}\):\(\frac{3}{5}\) =>	\ ( \ frac {2} {3} \ ) : \ ( \ frac {3} {5} \ )
\(2^3\) =>	\ ( 2 ^ 3 \ )
2,07 x \(10^6\) =	2,07 x \ (10^6 \ )
6,7 x \(10^{-6}\) =	6,7 x \ (10^ {-6} \ )
\(\sqrt {16}\) =	\ ( \ sqrt {16} \ )
\(\sqrt {200}\) \(\approx\) 14	\ ( \ sqrt {200} \ ) \ ( \ approx \ ) 14
\(\sqrt[i]{R}\) = r, rd	\ ( \ sqrt [i] {R} \ ) = r, rd índice Radicando raíz, residuo
2,3454545... => 2,3\(\stackrel{\frown}{45}\)	2,3 \ ( \ stackrel { \ frown} {45} \ ) Decimal periódico.
\(\mathbf{texto·en·negritas}\)	\ ( \ mathbf {texto·en·negritas} \ ) Negrita.
Arco: 2,3\(\overparen{45}\)	2,3 \ ( \ overparen {45} \ )
Arco, periódico: 2,3\(\stackrel\frown{45}\)	2,3 \ ( \ stackrel \ frown {45} \ )
Segmento: 2,3\(\overline{457}\)	2,3 \ ( \ overline {457} \ )
Circunflejo largo: 2,3\(\widehat{457}\)	2,3 \ ( \ widehat {457} \ )
Doble flecha: \(\overleftrightarrow{AB}\)	\ ( \ overleftrightarrow {AB} \ )
\(\overline{X I V} DC LXX IX\) = 14.679	\ ( \ overline {X I V} DC LXX IX \ )
Área Círculo : \(\pi\) × \(r^2\) => π ·r²	\ ( \ pi \ ) × \ ( r ^ 2 \ )
Potencias, Límites y otras fórmulas lal2 [1^2] \(\lim_{x to infty} exp(-x) = 0\) \(\a bmod b\) [x equiv a ] [pmod b] \(\pi\) [k_{n+1} = n^2 + k_n^2 – k_{n-1}] Paréntesis [( a )] [ [ b ]] [ { c }] [ \| d \|] [ \| e \|] [langle f rangle] [lfloor g rfloor] [lceil h rceil] [ ulcorner i urcorner]	?
\(\pi\) \(\alpha\)	\ ( \ pi \ ) \ ( \ Alpha \ )

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	Erstellt von Ulises Yo vor etwa 6 Jahre