4761183
Beschreibung
Karteikarten von Thomas Allaker, aktualisiert more than 1 year ago
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Erstellt von Thomas Allaker
vor mehr als 8 Jahre
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| Frage | Antworten |
| If ax^2 + bx + c = 0, what is the quadratic formula which will find all answers of x? | |
| When differentiating, what is the derivative of the function x^n? | nx^(n-1) |
| When integrating, what is the integral of the function x^n? | (x^(n + 1))/(n + 1) + c |
| What is the formula for completing the square? | x^2 + bx = (x + b/2)^2 - (b/2)^2 |
| What is the discriminant? | b^2 - 4ac |
| In what form can a quadratic equation be written by completing the square? | y = p[(x-q)^2 + r] |
| What can the equation y = p[(x-q)^2 + r] tell us about a graph of y = ax^2 + bx + c? | Turning point = (q, pr) Axis of symmetry = q It's the graph of y = x^2 translated q places horizontally and r places vertically |
| How do you rationalise n/x where x is an irrational denominator? | n/x * y/y where y = x with all signs reversed |
| How do numbers in the brackets of a function and outside the brackets of a function translate the curve f(x)? | Numbers inside the bracket do the opposite of their sign horizontally, whereas numbers outside do as their sign suggests, vertically |
| How do you find the gradient of a line passing through a point with a given gradient? | y - y1 = m(x - x1) where y1 and x1 are the coordinates of the point |
| How do you calculate the distance between two given points? | Sqrt((x2 - x1)^2 + (y2 - y1)^2) where x1 and y1 are the coordinates of point 1 and x2 and y2 are the coordinates of point 2 |
| How do you find the midpoint of two given points? | ((x1 + x2)/2, (y1 + y2)/2) where x1 and y1 are the coordinates of point 1 and x2 and y2 are the coordinates of point 2 |
| What is the formula for the nth term in an arithmetic progression? | Un = a + (n - 1)d |
| What are the two equations for the sum of an arithmetic sequence? | Sn = n/2 * [2a + (n - 1)d] Sn = n/2 * [a + L] |
| What property of a curve does differentiating find? | The gradient of the tangent to the curve |
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