4392742
Description
Flashcards by ashiana121, updated more than 1 year ago
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Created by ashiana121
almost 9 years ago
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| Question | Answer |
| What are the 5 transition metals we study that form metal aqua ions? | Co Cu Fe Al Cr Fe |
| Which are 2+? | Co Cu Fe |
| Which are 3+? | Al Cr Fe |
| How many water ligands are attached to each of the central metal ions? | 6 |
| What are the 3 reagents we need to remember the reaction colours of? | Na₂CO₃ OH¯ NH₃ |
| What colour is the [Cu(H₂O)₆]²⁺ ion? | Blue |
| What colour is the [Cr(H₂O)₆]³⁺ ion? | Ruby |
| What colour is the [Al(H₂O)₆]³⁺ ion? | Colourless |
| What colour is the [Co(H₂O)₆]²⁺ ion? | Pink |
| What colour is the [Fe(H₂O)₆]³⁺ ion? | Violet |
| What colour is the [Fe(H₂O)₆] ²⁺ ion? | Green |
| When the [Fe(H₂O)₆] ²⁺ ion is reacted with OH¯ or NH₃, what is formed? (Formula and physical appearance) | Green precipitate Fe(H₂O)₄(OH)₂ |
| If the same ion ([Fe(H₂O)₆] ²⁺) is reacted with Na₂CO₃ the physical appearance is the same however the formula of the precipitate is different. What is this formula? | FeCO₃ |
| The [Fe(H₂O)₆]²⁺ reactions are different to the [Fe(H₂O)₆]³⁺ reactions. What colour precipitate is formed in all the reactions of the ³⁺ ion? (with Na₂CO₃, OH¯ and NH₃) | Brown |
| How many moles of [Fe(H₂O)₃(OH)₃] are made in the reactions of [Fe(H₂O)₆]³⁺ with OH- or NH₃? | 1 |
| How many are made in the reaction with Na₂CO₃? | 2 |
| What colour precipitate is made when [Co(H₂O)₆]²⁺ is reacted with Na₂CO₃? | Pink |
| What is the formula of this precipitate? | CoCO₃ |
| The same colour precipitate is formed when [Co(H₂O)₆]²⁺ is reacted with dilute ammonia and with OH-. What colour is this precipitate? | Blue-green |
| Is the formula of the precipitate the same? | Yes |
| What is the formula? | Co(H₂O)₄(OH)₂ |
| What colour solution is formed when [Co(H₂O)₆]²⁺ reacts with excess ammonia? | Straw |
| What is the formula of the complex ion which makes this solution appear straw coloured? | [Co(NH₃)₆]²⁺ |
| The [Al(H₂O)₆]³⁺ ion is colourless. In what reaction (with ammonia/hydroxide, excess ammonia, excess hydroxide or sodium carbonate) does the solution remain colourless? | Excess hydroxide |
| What is the formula of the ion formed in this reaction? | [Al(OH)₄]¯ |
| The same colour precipitate is formed in the three other reactions. What colour is this? | White |
| For the reactions with ammonia/hydroxide, excess ammonia, and sodium carbonate the same white precipitate is made. What is the formula of this? | Al(H₂O)₃(OH)₃ |
| What is the only difference between the reactions of hydroxide/ammonia and the reaction of sodium carbonate? | Reaction with sodium carbonate - 2 moles of Al(H₂O)₃(OH)₃ formed |
| What colour is the [Cr(H₂O)₆]³⁺ ion? | Ruby |
| When it is reacted with excess ammonia, what colour does the solution go and what is the formula of the ion responsible for the appearance of this colour? | Purple [Cr(NH₃)₆]³⁺ |
| Out of the reactions of [Cr(H₂O)₆]³⁺ with - hydroxide/ammonia -excess hydroxide -sodium carbonate Which forms a green precipitate and which forms a green solution? | [Cr(H₂O)₆]³⁺ and hydroxide/ammonia = green precipitate [Cr(H₂O)₆]³⁺ and excess hydroxide = green solution [Cr(H₂O)₆]³⁺ and sodium carbonate = green solution |
| What is the formula of the green precipitate? | Cr(H₂O)₃(OH)₃ 2[Cr(H₂O)₃(OH)₃] for reaction with Na₂CO₃ |
| What is the formula of the green solution formed when the [Cr(H₂O)₆]³⁺ reacts with an excess of hydroxide? | [Cr(H₂O)₆]³¯ |
| The [Cu(H₂O)₆]²⁺ ion is ____ | Blue |
| When the [Cu(H₂O)₆]²⁺ ion reacts with hydroxide or ammonia (not in excess) or with an excess of hydroxide, a ____ __________ is formed | Blue precipitate |
| What is the formula of this precipitate? | Cu(H₂O)₄(OH)₂ |
| A deep blue solution is formed when [Cu(H₂O)₆]²⁺ reacts with... | Excess NH₃ |
| What is the charge of the complex ion that makes this solution appear deep blue? | 2+ |
| What is the formula of this complex ion? | [Cu(NH₃)₄(H₂O)₂]²⁺ |
| What is happens when the [Cu(H₂O)₆]²⁺ ion reacts with sodium carbonate? | CuCO₃, a green-blue precipitate is formed |
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