Probabilités

Description

Flashcards on Probabilités, created by louise.chardon94 on 29/03/2016.
louise.chardon94
Flashcards by louise.chardon94, updated more than 1 year ago
louise.chardon94
Created by louise.chardon94 over 8 years ago
3
1

Resource summary

Question Answer
pour les symboles compliqués
P(A U B) = = P(A) + P(B)
P(IA) = = 1 - P(A)
P(A U B) = = P(A) + P(B) - P(A II B)
E(aX + b) = = aE(X) + b
V(aX + b) = = a puiss (2)V(X)
PA(B) = = (P(A II B)) / (P(A))
Evénement indépendants ssi P(A II B) = = P(A) x P(B) Lorsque P(A) diff 0 et PA(B) = P(B)
Schema Bernoulli Loi Binomial P(X=k) = (n k) x p puiss (k) (1 - p) puiss (n-k) B (n,p)
E(X) = V(X) = o(X) = = np = np(1-p) = rac de (np(1-p))
densité nv chapitre
E(X) = = S [ ; ] t f(t) dt = (a + b) / 2
f(t) = = 1/(b-a) = (d-c)/(b-a)
loi expo f(t) = Ye puiss (-Yt)
loi sans mémoire PX>t(X>t+h) = P(X>h)
E(X) = = 1/Y
Demi-vie t1/2 = ln2/Y
loi normal f(x) = 1/ (rac de (2pi)) X e puiss (-xcarré/2)
normalcdf --> cherche probe invNorm --> cherche u dans P(x=u)=2 (lower,upper, moyenne, écart type) (2,moyenne, écart type)
P(-1<X<1) P(-2<X<2) P(-3<X<3) = 0,683 = 0,954 = 0,997
variable = = (X - moyenne) / écart type
Show full summary Hide full summary

Similar

3. The Bolshevik's Seizure of Power
ShreyaDas
CHEMISTRY C1 2
x_clairey_x
How Villainy is Depicted in Macbeth
scarletsnow491
P4: Explaining motion
thegeekymushroom
Geography AQA Revison topics Migration, Population Change, Youthful Populations and more
dburns8731
Chapter 5: Short-term and Working Memory
krupa8711
الانماط الاساسية لوراثة الانسان
Jamilah-Ahmed
The Reformation
keeva byrne
Literary Techniques in Othello
Rebecca Hunter
Preguntas del Pensamiento Matemático
Paola Rodríguez