Trig Identities

Description

Maths Flashcards on Trig Identities, created by anthonyjwheeler on 26/04/2013.
anthonyjwheeler
Flashcards by anthonyjwheeler, updated more than 1 year ago
anthonyjwheeler
Created by anthonyjwheeler over 11 years ago
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Resource summary

Question Answer
Sin² θ+Cos² θ= 1
Tan² θ+1= Sec² θ
Cot²+1= Cosec² θ
Tan θ= Sin θ/Cos θ
Sin θ/Cos θ= Tan θ
Cos θ/Sin θ= Cot θ
Cot θ= 1/Tan θ
Sec θ= 1/Cos θ
Cosec θ= 1/Sin θ
1/Sin θ= Cosec θ
1/Cos θ= Sec θ
1/Tan θ= Cot θ
Cos²θ= 1-Sin²θ
Cos²θ-1= Sin²θ
Sin²θ= 1-Cos²θ
-Sin²θ= Cos²θ-1
Tan²θ= Sec²θ-1
Sec²θ-Tan²θ= 1
Tan²θ-Sec²θ= -1
-Tan²θ= 1-Sec²θ
Cot²θ= Cosec²θ-1
Cot²θ-Cosec²θ= -1
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