9672085
Description
Flashcards by Bilal Hussain, updated more than 1 year ago
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Created by Bilal Hussain
over 7 years ago
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| Question | Answer |
| Expand: 3(x + 2) The "3" on the outside must multiply both terms inside the brackets. | = 3x + 6 If: 3y(x + 2) ,then you would do the same with the "y" = 3yx + 6y |
| Expand: (x + 5)x Even though the brackets appear first, you still multiply the outside "x" with both terms inside the brackets. | = x² + 5x |
| Expand: x(x - y) The "x" on the outside must multiply both terms inside the brackets. | = x² - xy |
| Expand: -3a²(3 - b) Both terms inside the brackets must be multiplied by "-3a²" | = -9a² + 3a²b |
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