ГОС по БД #1

Question 1 of 89

1

Define a degree of a relation

Select one of the following:

How many rows a table has
how long each tuple is, or how many columns the table has
how many different tuples there are
how many different datatypes table has

Explanation

Question 2 of 89

1

Define a cardinality of a relation

Select one of the following:

how long each tuple is
how many columns the table has
how many different tuples there are, how many rows a table has
how many different datatypes table has

Explanation

Question 3 of 89

1

Which of the following refers to union-compatibility requirements ?

Select one of the following:

Same number of columns
Same number of rows
Same number of tuples
Different domains

Explanation

Question 4 of 89

1

Which of the following refers to union-compatibility requirements ?

Select one of the following:

Corresponding columns have the same domains
Same number of rows
Same number of tuples
Corresponding columns have the same fields

Explanation

Question 5 of 89

1

Define a domain

Select one of the following:

restrict the possible values a tuple can assign to each attribute
relations to each other
uniquely identifies each tuple that appears in a relation
minimality of the attribute

Explanation

Question 6 of 89

1

Define a foreign key

Select one of the following:

restrict the possible values a tuple can assign to each attribute
relations to each other
uniquely identifies each tuple that appears in a relation
minimality of the attribute

Explanation

Question 7 of 89

1

Define a primary key

Select one of the following:

restrict the possible values a tuple can assign to each attribute
relations to each other
uniquely identifies each tuple that appears in a relation
datatypes of attributes

Explanation

Question 8 of 89

1

Define restrict

Select one of the following:

stop the user from doing it
let the changes flow on
make referencing values the default for their column
make referencing values null

Explanation

Question 9 of 89

1

Define cascade

Select one of the following:

stop the user from doing it
let the changes flow on
make referencing values the default for their column
make referencing values null

Explanation

Question 10 of 89

1

Define set default

Select one of the following:

stop the user from doing it
let the changes flow on
make referencing values the default for their column
make referencing values null

Explanation

Question 11 of 89

1

Define set null

Select one of the following:

stop the user from doing it
let the changes flow on
make referencing values the default for their column
make referencing values null

Explanation

Question 12 of 89

1

Define Data Definition Language

Select one of the following:

Specify database format
Specify access controls (privileges)
Specify and retrieve database contents
Specify table attribute uniqueness

Explanation

Question 13 of 89

1

Define Data Control Language

Select one of the following:

Specify access controls (privileges)
Specify database format
Specify and retrieve database contents
Specify table attribute uniqueness

Explanation

Question 14 of 89

1

Define Data Manipulation Language

Select one of the following:

Specify table attribute uniqueness
Specify database format
Specify access controls (privileges)
Specify and retrieve database contents

Explanation

Question 15 of 89

1

Which of the following does not refer to DBMS tools

Select one of the following:

Oracle
PostgreSQL
MySQL
Python

Explanation

Question 16 of 89

1

Which of the following is used to provide privilege to only a particular attribute?

Select one of the following:

Grant select on employee to finance
Grant update(salary, rate) on employee to finance
Grant update(salary) on employee to finance
Grant delete to finance

Explanation

Question 17 of 89

1

Which of the following statement is used to remove the privilege from the user finance?

Select one of the following:

Remove update on employee from finance
Delete select on employee from finance
Revoke update on employee from finance
Grant update on employee from finance

Explanation

Question 18 of 89

1

Which of the following is true regarding views?

Select one of the following:

The user who creates a view cannot be given update authorization on a view without having update authorization on the relations used to define the view.
If a user creates a view on which no authorization can be granted, the system will allow the view creation request.
A user who creates a view receives all privileges on that view.

Explanation

Question 19 of 89

1

If we wish to grant a privilege and to allow the recipient to pass the privilege on to other users, we append the __________ clause to the appropriate grant command.

Select one of the following:

With grant
Grant user
With grant option
Grant pass privelege

Explanation

Question 20 of 89

1

Which of the following is used to avoid cascading of authorizations from the user?

Select one of the following:

Granted by current role
Revoke grant option for select on department from finance;
Revoke select on employee from finance, cashier restrict;
Revoke select on department from finance, cashier cascade;

Explanation

Question 21 of 89

1

Privileges are granted over some specified parts of a database, such as a

Select one of the following:

Schema
Environment
Relation Or view
Query statement

Explanation

Question 22 of 89

1

Prevention of access to the database by unauthorized users is referred to as:

Select one of the following:

Integrity
Productivity
Security
Reliability

Explanation

Question 23 of 89

1

Database Authentication refers to:

Select one of the following:

methods of restricting user access to system
controlling access to portions of database
all of the answers mentioned
controlling the operation on the data

Explanation

Question 24 of 89

1

A set of possible data values is called

Select one of the following:

attribute
degree
domain
tuple

Explanation

Question 25 of 89

1

A functional dependency between two or more non-key attributes is called

Select one of the following:

Partial transitive dependency
Functional dependency
Transitive dependency
Partial functional dependency

Explanation

Question 26 of 89

1

__ refers to the correctness and completeness of the data in a database.

Select one of the following:

Database security
Data constraint
Data integrity
Data independence

Explanation

Question 27 of 89

1

Which of the following creates a virtual relation for storing the query?

Select one of the following:

Function
Procedure
View
None of the mentioned

Explanation

Question 28 of 89

1

Which of the following is the syntax for views where v is view name?

Select one of the following:

Create view v as “query name”;
Create “query expression” as view;
Create view v as “query expression”;
Create view “query expression”;

Explanation

Question 29 of 89

1

Updating the value of the view

Select one of the following:

Will not change the view definition
Will not affect the relation from which it is defined
Will affect the relation from which it is defined
Cannot determine

Explanation

Question 30 of 89

1

Create view faculty as: Select ID, name, dept name from instructor; Find the error in this query.

Select one of the following:

Instructor
Select
None of the mentioned
View …as

Explanation

Question 31 of 89

1

Which of the following is a basic form of grant statement?

Select one of the following:

Grant ‘privilege list’ on ‘user/role list’ to ‘relation name or view name’;
Grant ‘privilege list’ to ‘user/role list’;
Grant ‘privilege list’ on ‘relation name or view name’ to ‘user/role list’;
Grant ‘privilege list’ on ‘relation name or view name’ on ‘user/role list’;

Explanation

Question 32 of 89

1

Retrieve all data from the table OFFICE { id,room, name}

Select one of the following:

Select *from office;
Select from office;
Select name from office;
Select *form office;

Explanation

Question 33 of 89

1

Retrieve office name from the table OFFICE {id, room, name}

Select one of the following:

Select *from office;
Select from office;
Select name from office;
Select *form office;

Explanation

Question 34 of 89

1

Retrieve office id from the table OFFICE {id, room, name}

Select one of the following:

Select *from office;
Select id from office;
Select name from office;
Select id form office;

Explanation

Question 35 of 89

1

Retrieve office id and room from the table OFFICE {id, room, name}

Select one of the following:

Select *from office;
Select id, room from office;
Select room name from office;
Select id form office;

Explanation

Question 36 of 89

1

Retrieve quantity of offices in the office table - OFFICE {id, rom, name}

Select one of the following:

Select avg (id) from office;
Select count (id) from office;
Select sum (id) from office;
Select max (id) from office;

Explanation

Question 37 of 89

1

Retrieve total number scholarship in the students table – STUDENTS {id, name, scholarship, registereddate, tutorid}

Select one of the following:

Select avg (scholarship) from office;
Select count (scholarship) from office;
Select sum (scholarship) from office;
Select max (scholarship) from office;

Explanation

Question 38 of 89

1

Retrieve quantity of students in the students table – STUDENTS {id, name, scholarship, registereddate, tutorid}

Select one of the following:

Select avg (id) from office;
Select count (id) from office;
Select sum (id) from office;
Select max (id) from office;

Explanation

Question 39 of 89

1

Sort students name by descending order - STUDENTS {id, name, scholarship, registereddate, tutorid}

Select one of the following:

Select name from students order by desc;
Select name from students group by desc;
Select *from students order by desc;
Select name form students order by desc;

Explanation

Question 40 of 89

1

Find an average scholarship of students - STUDENTS {id, name, scholarship, registereddate, tutorid}

Select one of the following:

Select avg (scholarship) from students;
Select count (scholarship) from students;
Select sum (scholarship) from students;
Select max (scholarship) from students;

Explanation

Question 41 of 89

1

Find maximum scholarship of students - STUDENTS {id, name, scholarship, registereddate, tutorid}

Select one of the following:

Select avg (scholarship) from students;
Select count (scholarship) from students;
Select sum (scholarship) from students;
Select max (scholarship) from students;

Explanation

Question 42 of 89

1

Find minimum scholarship of students - STUDENTS {id, name, scholarship, registereddate, tutorid}

Select one of the following:

Select avg (scholarship) from students;
Select count (scholarship) from students;
Select min (scholarship) from students;
Select max (scholarship) from students;

Explanation

Question 43 of 89

1

Retrieve offices’ name and tutors’, who work in CSSE department. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, OFFICEID (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

Select o.name, t.name from office o join tutor t on o.id=t.officeid where o.name = ‘CSSE’
Select o.name, t.name from office o join tutor t on o.id=t.id where o.name = ‘CSSE’
Select o.name, t.name from office o join tutor t on o.id=t.officeid where o.name = ‘csse’
Select o.name, t.name from office o join tutor t on o.id=t.officeid where o.name ‘CSSE’

Explanation

Question 44 of 89

1

Retrieve all offices’ name and tutors’, who work in departments. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

Select o.name, t.name from office o left join tutor t on o.id=t.officeid;
Select o.name, t.name from office o left join tutor t on o.id=t.id ;
Select o.name, t.name from office o right join tutor t on o.id=t.officeid;
Select o.name, t.name from office o right join tutor t on o.id=t.id ;

Explanation

Question 45 of 89

1

Retrieve students’ name, who have more than average scholarship. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

select s.name from students s where s.scholarship > (select avg (scholarship)from students);
select s.name from students s where s.scholarship > (select scholarship from students);
select s.name from students s where s.scholarship > avg (scholarship);
select s.name from students s where s.scholarship < avg (scholarship);

Explanation

Question 46 of 89

1

Retrieve students’ name, who registered in 10th of Jan 2016. Tables: STUDENTS {id (PK), name, scholarship, registereddate, tutorid }.

Select one of the following:

select name from students where registereddate = '2016-01-10';
select name from students where registereddate = '2016-10-10';
select name from students where registereddate = 2016-10-10;
select name from students where registereddate = '2016-01-01';

Explanation

Question 47 of 89

1

Retrieve tutors’ name, who have more than experience others along with their students name . Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

select t.name, s.name from tutor t join students s on t.id=s.tutorid where experience = (select max (experience) from tutor);
select t.name, s.name, max(experience) from tutor t join students s on t.id=s.tutorid;
select t.name, s.name from tutor t join students s on t.id=s.id where experience = (select max (experience) from tutor);

Explanation

Question 48 of 89

1

Retrieve tutors’ name, who have less experience than others along with their students name. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

select t.name, s.name from tutor t join students s on t.id=s.tutorid where experience = (select min (experience) from tutor);
select t.name, s.name, min(experience) from tutor t join students s on t.id=s.tutorid;
select t.name, s.name from tutor t join students s on t.id=s.id where experience = (select min (experience) from tutor);

Explanation

Question 49 of 89

1

Increase tutors experience and students’ scholarship twice. Retrieve experience and scholarship along with their names. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

select t.name,t.experience*2, s.name, s.scholarship*2 from tutor t join students s on t.id=s.tutorid;
select t.name,t.experience*2, s.name, s.scholarship*2 from tutor t join students s on t.id=s.id;
select t.name,t.experience*2, s.name, s.scholarship*2 from tutor t join tutor s on t.id=s.tutorid;
select t.name,t.experience*2, s.name, s.scholarship*2 from tutor t join tutor s on t.id=s.id;

Explanation

Question 50 of 89

1

Retrieve office, tutor and students name, but tutors name should have y value. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st on t.id=st.tutorid where t.name like '%y%';
select o.name, t.name, st.name from tutor t join office o o.id=t.officeid join students st on t.id=st.tutorid where t.name like '%y%';
select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st t.id=st.tutorid where t.name like '%y%';
select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st on t.id=st.id where t.name like '%y%';

Explanation

Question 51 of 89

1

Retrieve office, tutor and students name, but tutors name should not have y value. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutored (FK references tutor (id))}.

Select one of the following:

select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st on t.id=st.tutorid where t.name not like '%y%';
select o.name, t.name, st.name from tutor t join office o o.id=t.officeid join students st on t.id=st.tutorid where t.name not like '%y%';
select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st t.id=st.tutorid where t.name not like '%y%';
select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st on t.id=st.id where t.name not like '%y%';

Explanation

Question 52 of 89

1

Retrieve students name and scholarship along with their department name, who have scholarship between 4000 and 5000. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

select s.name, s.scholarship, o.name from office o join tutor t on o.id=t.officeid join students s on t.id=s.tutorid where s.scholarship between 4000 and 5000;
select s.name, s.scholarship, o.name from office o join tutor t on o.id=t.officeid join students s on t.id=s.tutorid where s.scholarship 4000 and 5000;
select s.name, s.scholarship, o.name from tutor t join students s on t.id=s.tutorid where s.scholarship between 4000 and 5000;
select s.name, s.scholarship, o.name from tutor t join students s on t.id=s.tutorid where s.scholarship >=4000

Explanation

Question 53 of 89

1

Retrieve information about office and their tutors as well. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.d

Select one of the following:

select *from office o join tutor t on o.id=t.officeid;
select *from office o join tutor t in o.id=t.officeid;
select *form office o join tutor t on o.id=t.officeid;
select *from office o join tutor t on o.id=t.id;

Explanation

Question 54 of 89

1

Retrieve office name and tutor name, which have maximum experienced tutors. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

select o.name, t.name from office o join tutor t on o.id=t.officeid where t.experience = (select max (experience) from tutor);
select o.name, t.name from office o join tutor t on o.id=t.officeid where t.experience = (select min (experience) from tutor);
select o.name, t.name from office o join tutor t on o.id=t.officeid where t.experience = (select high (experience) from tutor);
select o.name, t.name from office o join tutor t on o.id=t.officeid where t.experience = (select low (experience) from tutor);

Explanation

Question 55 of 89

1

Retrieve all tutors and students names. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

select t.name, s.name from tutor t full join students s on t.id=s.tutorid;
select t.name, s.name from tutor t full join students s t.id=s.tutorid;
select t.name, s.name from tutor t full join students s t.id=s.id;
select t.name, s.name from tutor t full join students s on t.id=s.id;

Explanation

Question 56 of 89

1

Retrieve tutors’ name and the number of students for each of them. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

select count (s.name) as numberofstudents, t.name from tutor t join students s on t.id=s.tutoridgroup by t.name;
select count (s.name) as numberofstudents, t.name from tutor t join students s on t.id=s.tutorid;
select count (s.name) as numberofstudents, t.name from tutor t join students s on t.id=s.idgroup by t.name;
select count (s.name) as numberofstudents, t.name from tutor t join students s on t.id=s.id;

Explanation

Question 57 of 89

1

Retrieve office name and the number of students for each of them. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Select one of the following:

select count (s.name) as numberofstudents, o.name from tutor t join students s on t.id=s.tutoridjoin office o on o.id=t.officeid group by o.name;
select count (s.name) as numberofstudents, o.name from students s on join office o on o.id=s.id group by o.name;
select count (s.name) as numberofstudents, o.name from tutor t join students s on t.id=s.tutoridjoin office o o.id=t.officeid group by o.name;
select count (s.name) as numberofstudents, o.name from tutor t join students s on t.id=s.idjoin office o on o.id=t.id group by o.name;

Explanation

Question 58 of 89

1

Retrieve all students’ name and scholarship, tutors name except students who have scholarship 3000$. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Select one of the following:

select s.name, t.name from students s join tutor t on s.tutorid=t.id where s.scholarship <> 3000;
select s.name, t.name from students s join tutor t on s.tutorid=t.id where s.scholarship = 3000;
select s.name, t.name from students s join tutor t on s.tutorid=t.id where s.scholarship < 3000;
select s.name, t.name from students s join tutor t on s.tutorid=t.id where s.scholarship is 3000;

Explanation

Question 59 of 89

1

How many types of anomalies exist?

Select one of the following:

1
2
3
4

Explanation

Question 60 of 89

1

Which of the following anomaly does not exist?

Select one of the following:

Creation anomaly
Deletion anomaly
Insertion anomaly
Modification anomaly

Explanation

Question 61 of 89

1

When an insertion anomaly occurs?

Select one of the following:

we are prevented from inserting some data into a relation until other data can be supplied
deletion leads to an unintended loss of data
it is possible that not all data needs to be changed will always be changed
it does not occur

Explanation

Question 62 of 89

1

When a modification anomaly occurs?

Select one of the following:

it is possible that not all data needs to be changed will always be changed
we are prevented from inserting some data into a relation until other data can be supplied
deletion leads to an unintended loss of data
it does not occur

Explanation

Question 63 of 89

1

When a deletion anomaly occurs?

Select one of the following:

deletion leads to an unintended loss of data
it is possible that not all data needs to be changed will always be changed
we are prevented from inserting some data into a relation until other data can be supplied
it does not occur

Explanation

Question 64 of 89

1

Define inner join

Select one of the following:

selects all rows from both tables as long as there is a match between the columns in both tables
returns all rows from the left table (1), with the matching rows in the right table (2)
returns all rows from the right table (2), with the matching rows in the right table (1)
returns all rows from the left table (1) and from the right table (2)

Explanation

Question 65 of 89

1

Define left join

Select one of the following:

returns all rows from the left table (1), with the matching rows in the right table (2)
selects all rows from both tables as long as there is a match between the columns in both tables
returns all rows from the right table (2), with the matching rows in the right table (1)
returns all rows from the left table (1) and from the right table (2)

Explanation

Question 66 of 89

1

Define right join

Select one of the following:

returns all rows from the right table (2), with the matching rows in the left table (1)
returns all rows from the left table (1), with the matching rows in the right table (2)
selects all rows from both tables as long as there is a match between the columns in both tables
returns all rows from the left table (1) and from the right table (2)

Explanation

Question 67 of 89

1

Define full join

Select one of the following:

returns all rows from the left table (1) and from the right table (2)
returns all rows from the right table (2), with the matching rows in the right table (1)
returns all rows from the left table (1), with the matching rows in the right table (2)
selects all rows from both tables as long as there is a match between the columns in both tables

Explanation

Question 68 of 89

1

Define an union

Select one of the following:

сombines the result set of two or more select statements
returns all rows from the left table (1) and from the right table (2)
returns all rows from the right table (2), with the matching rows in the right table (1)
returns all rows from the left table (1), with the matching rows in the right table (2)

Explanation

Question 69 of 89

1

INNER JOIN and JOIN are the same

Select one of the following:

True
False

Explanation

Question 70 of 89

1

Define self join

Select one of the following:

returns all rows from the table that references to yourself
returns all rows from the right table (2), with the matching rows in the right table (1)
selects all rows from both tables as long as there is a match between the columns in both tables
returns all rows from the left table (1) and from the right table (2)

Explanation

Question 71 of 89

1

How many types of functional dependencies exist

Select one of the following:

1
2
3
0

Explanation

Question 72 of 89

1

Which of the following does not to the functional dependency

Select one of the following:

equational
full
transitive
partial

Explanation

Question 73 of 89

1

Which of the following represent a full dependency?

Select one of the following:

it exists in relation if there is no attribute A that can be removed from X and the dependency still holds
if there exists an attribute A that is part of X that can be removed from X and the dependency still holds
x->y dependency in relation R and x, y , z are columns in R. X->Y and Y>Z in R. Final: X->Y
all above mentioned

Explanation

Question 74 of 89

1

Which of the following represent a partial dependency?

Select one of the following:

if there exists an attribute A that is part of X that can be removed from X and the dependency still holds
it exists in relation if there is no attribute A that can be removed from X and the dependency still holds
x->y dependency in relation R and x, y , z are columns in R. X->Y and Y>Z in R. Final: X->Y
all above mentioned

Explanation

Question 75 of 89

1

Which of the following represent a transitive dependency?

Select one of the following:

x->y dependency in relation R and x, y , z are columns in R. X->Y and Y->Z in R. Final: X->Y
if there exists an attribute A that is part of X that can be removed from X and the dependency still holds
it exists in relation if there is no attribute A that can be removed from X and the dependency still holds
all above mentioned

Explanation

Question 76 of 89

1

When was first normalization developed?

Select one of the following:

1970
1972
1973
1974

Explanation

Question 77 of 89

1

When was second normalization developed?

Select one of the following:

1971
1972
1973
1974

Explanation

Question 78 of 89

1

When was Boyce–Codd normalization developed?

Select one of the following:

1974
1972
1973
1971

Explanation

Question 79 of 89

1

Who is an inventor of relational model?

Select one of the following:

Edgar F.Codd
Raymond Boyce
Marine Jone
John Salamondor

Explanation

Question 80 of 89

1

Which of the following refers to the requirement of 1NF

Select one of the following:

Each cell should be single valued
Entries in a column are same type
Rows uniquely identified
All above mentioned

Explanation

Question 81 of 89

1

Which of the following refers to the requirement of 2NF

Select one of the following:

All attributes (non-key columns) dependent on the key
Each cell should be single valued
All fields (columns) can be determined only by the key in the table and no other column
All above mentioned

Explanation

Question 82 of 89

1

Which of the following refers to the requirement of 3NF

Select one of the following:

All fields (columns) can be determined only by the key in the table and no other column
All attributes (non-key columns) dependent on the key
Each cell should be single valued
All above mentioned

Explanation

Question 83 of 89

1

Define avg function

Select one of the following:

Returns average value
Returns total value
Returns the first value
Converts to lowercase

Explanation

Question 84 of 89

1

Which function is used to retrieve quantity of rows

Select one of the following:

count
sum
max
avg

Explanation

Question 85 of 89

1

Retrieve avg scholarship of students. Tables: office {id (PK), locations, name}, tutor {id (PK), name, officeid (FK references office (id)), experience}, students {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Select one of the following:

select avg (scholarship) from students;
select aveg (scholarship) from students;
select avr (scholarship) from students;
select avgr (scholarship) from students;

Explanation

Question 86 of 89

1

Retrieve students’, scholarship and teacher's’ name, who have more than average scholarship. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Select one of the following:

select s.name, s.scholarship, t.name from students s, tutor t where t.id=s.tutorid and s.scholarship> (select avg(scholarship) from students)
select s.name, s.scholarship, t.name from students s, tutor t where t.id=s.tutorid and s.scholarship> avg(scholarship)
select s.name, s.scholarship, t.name from students s, tutor t where s.scholarship> (select avg(scholarship) from students)
select s.name, avg(s.scholarship), t.name from students s, tutor t

Explanation

Question 87 of 89

1

Retrieve students’, scholarship and teacher's’ name, who have more than average scholarship AND increase those students twice. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Select one of the following:

select s.name, s.scholarship*2, t.name from students s, tutor t where t.id=s.tutorid and s.scholarship> (select avg(scholarship) from students)
select s.name, s.scholarship*2, t.name from students s, tutor t where t.id=s.tutorid and s.scholarship> avg(scholarship)
select s.name, s.scholarship*2, t.name from students s, tutor t where s.scholarship> (select avg(scholarship) from students)
select s.name, avg(s.scholarship)*2, t.name from students s, tutor t

Explanation

Question 88 of 89

1

Retrieve students and mentors name, but mentors registration date should be before students registration date. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Select one of the following:

select s.name, m.name from students s join students m on s.tutorid=m.tutorid where s.registereddate<m.registereddate;
select s.name, m.name from students s join students m on s.tutorid=m.tutorid where s.registereddate>m.registereddate;
select s.name, m.name from students s join students m on s.tutorid=m.tutorid;
select s.name, m.name from students s join students m on s.registereddate=m.registereddate;

Explanation

Question 89 of 89

1

Retrieve the highest experience from tutor. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Select one of the following:

select max (experience) from tutor;
select min (experience) from tutor;
select max (t.experience) from tutor t group by t.name;
select min (t.experience) from tutor t group by t.name;

	Created by хомяк убийца over 5 years ago

God Philosophy Quiz on ГОС по БД #1, created by хомяк убийца on 23/03/2019.

ГОС по БД #1

ГОС по БД #1

Question 1 of 89

Define a degree of a relation

Select one of the following:

Explanation

Question 2 of 89

Define a cardinality of a relation

Select one of the following:

Explanation

Question 3 of 89

Which of the following refers to union-compatibility requirements ?

Select one of the following:

Explanation

Question 4 of 89

Which of the following refers to union-compatibility requirements ?

Select one of the following:

Explanation

Question 5 of 89

Define a domain

Select one of the following:

Explanation

Question 6 of 89

Define a foreign key

Select one of the following:

Explanation

Question 7 of 89

Define a primary key

Select one of the following:

Explanation

Question 8 of 89

Define restrict

Select one of the following:

Explanation

Question 9 of 89

Define cascade

Select one of the following:

Explanation

Question 10 of 89

Define set default

Select one of the following:

Explanation

Question 11 of 89

Define set null

Select one of the following:

Explanation

Question 12 of 89

Define Data Definition Language

Select one of the following:

Explanation

Question 13 of 89

Define Data Control Language

Select one of the following:

Explanation

Question 14 of 89

Define Data Manipulation Language

Select one of the following:

Explanation

Question 15 of 89

Which of the following does not refer to DBMS tools

Select one of the following:

Explanation

Question 16 of 89

Which of the following is used to provide privilege to only a particular attribute?

Select one of the following:

Explanation

Question 17 of 89

Which of the following statement is used to remove the privilege from the user finance?

Select one of the following:

Explanation

Question 18 of 89

Which of the following is true regarding views?

Select one of the following:

Explanation

Question 19 of 89

If we wish to grant a privilege and to allow the recipient to pass the privilege on to other users, we append the __________ clause to the appropriate grant command.

Select one of the following:

Explanation

Question 20 of 89