Suma y Resta de FRACCIONES: a/b ± c/d = (ad ± bc) / bd Con reducción, e impropia (>1) en mixto.
|
Created by JL Cadenas
over 10 years ago
|
|
|
Copied by JULIAN SANCHEZ FLORES
over 4 years ago
|
|
Close
|
|
Created by JL Cadenas
over 10 years ago
|
|
|
|
Copied by JULIAN SANCHEZ FLORES
over 4 years ago
|
|
\(\frac {2}{3}\) + \(\frac {3}{4}\) =
\(\frac {1}{4}\) + \(\frac {2}{3}\) =
\(\frac {1}{2}\) + \(\frac {3}{4}\) =
\(\frac {1}{2}\) + \(\frac {1}{3}\) =
\(\frac {2}{3}\) + \(\frac {1}{2}\) =
\(\frac {1}{3}\) + \(\frac {3}{4}\) =
\(\frac {3}{4}\) + \(\frac {1}{5}\) =
\(\frac {2}{5}\) + \(\frac {1}{3}\) =
\(\frac {2}{5}\) + \(\frac {1}{2}\) =
\(\frac {1}{3}\) + \(\frac {1}{5}\) =
\(\frac {2}{3}\) + \(\frac {3}{5}\) =
\(\frac {3}{5}\) + \(\frac {1}{3}\) =
\(\frac {3}{5}\) – \(\frac {1}{3}\) =
\(\frac {2}{3}\) – \(\frac {1}{4}\) =
\(\frac {3}{4}\) – \(\frac {2}{3}\) =
\(\frac {3}{4}\) – \(\frac {1}{2}\) =
\(\frac {1}{2}\) – \(\frac {1}{3}\) =
\(\frac {2}{3}\) – \(\frac {1}{2}\) =
\(\frac {3}{4}\) – \(\frac {1}{3}\) =
\(\frac {3}{4}\) – \(\frac {1}{5}\) =
\(\frac {2}{5}\) – \(\frac {1}{3}\) =
\(\frac {1}{2}\) – \(\frac {2}{5}\) =
\(\frac {1}{3}\) – \(\frac {1}{5}\) =
\(\frac {2}{3}\) – \(\frac {3}{5}\) =
