What is the output of the following code snippet: (You can see the picture too)
if 'bar' in {'foo': 1, 'bar': 2, 'baz': 3}:
print(1)
print(2)
if 'a' in 'qux':
print(3)
print(4)

The following if/elif/else statement will raise a KeyError exception:
d = {'a': 0, 'b': 1, 'c': 0}

if d['a'] > 0:
print('ok')
elif d['b'] > 0:
print('ok')
elif d['c'] > 0:
print('ok')
elif d['d'] > 0:
print('ok')
else:
print('not ok')

Shown below is a diagram of a simple dictionary:

Which of the following is not a valid way to define this dictionary in Python:

What is the output of the following code snippet:
d = {'foo': 1, 'bar': 2, 'baz': 3}
while d:
print(d.popitem())
print('Done.')

The function sqrt() from the math module computes the square root of a number.

Will the highlighted line of code raise an exception?
x = -100
from math import sqrt
x > 0 and sqrt(x)

What is value of this expression:
'a' + 'x' if '123'.isdigit() else 'y' + 'b'