RUS L35 - 39

Descripción

(GI and Renal + Blood and Acid-Base) HUBS192 Test sobre RUS L35 - 39, creado por Mer Scott el 29/09/2017.
Mer Scott
Test por Mer Scott, actualizado hace más de 1 año
Mer Scott
Creado por Mer Scott hace alrededor de 7 años
31
2

Resumen del Recurso

Pregunta 1

Pregunta
Chronic renal failure can cause anaemia.
Respuesta
  • True
  • False

Pregunta 2

Pregunta
Which of these is an unhealthy glomerular filtration rate (GFR)?
Respuesta
  • 22L/hour
  • 150L/day
  • 125mL/min

Pregunta 3

Pregunta
Choose the incorrect statement about renal blood flow.
Respuesta
  • It requires high pressure.
  • It is 20-25% of cardiac output.
  • It is at a rate of about 2-2.4L/min.

Pregunta 4

Pregunta
There are forces which drive glomerular filtration and those that oppose it. The effective filtration pressure is always about [blank_start]+10[blank_end]mmHg. You can calculate it by adding together the forces that drive filtration (glomerular [blank_start]hydrostatic[blank_end] pressure and capsular [blank_start]osmotic[blank_end] pressure) and minusing the forces that oppose filtration (glomerular [blank_start]osmotic[blank_end] pressure and capsular [blank_start]hydrostatic[blank_end] pressure). Remember that [blank_start]capsular[blank_end] osmotic pressure is negligible i.e. zero.
Respuesta
  • +10
  • +20
  • +30
  • hydrostatic
  • osmotic
  • osmotic
  • hydrostatic
  • osmotic
  • hydrostatic
  • hydrostatic
  • osmotic
  • capsular
  • glomerular

Pregunta 5

Pregunta
Which equation describes renal clearance?
Respuesta
  • Cs = (Us x V) / Ps (clearance of substance is equal to the concentration of the substance in the urine, times the volume of urine per unit time, divided by the concentration of the substance in the plasma)
  • Cs = (Ps x V) / Us (clearance of substance is equal to the concentration of the substance in the plasma, times the volume of urine per unit time, divided by the concentration of the substance in the urine)
  • Cs = (Us / V) x Ps (clearance of substance is equal to the concentration of the substance in the urine, divided by the volume of urine per unit time, times the concentration of the substance in the plasma)

Pregunta 6

Pregunta
Choose the incorrect statement about glomerular filtration rate(GFR).
Respuesta
  • The GFR declines slowly with age.
  • To measure renal clearance we need a molecule that is not reabsorbed, secreted, or metabolised
  • Inulin or creatinine can be used to calculate GFR but inulin is commonly used clinically because it is a waste product of the muscles, whereas creatinine must be injected
  • GFR is fairly normal even if only 'one kidney' is intact. (half of nephrons)

Pregunta 7

Pregunta
The filtration fraction is the amount of the plasma (non-cellular component of blood—red blood cells are too big) which is filtered through the glomerulus. It can be calculated by [blank_start]multiplying[blank_end] the glomerular filtration rate by the renal [blank_start]plasma[blank_end] flow rate. (The renal plasma flow rate can be taken as [blank_start]half[blank_end] of the renal blood flow, i.e. if renal blood flow is 1.25L/min, renal plasma flow is [blank_start]625ml[blank_end]/min.) The equation is then [blank_start]FF = GFR x RPF[blank_end].
Respuesta
  • multiplying
  • dividing
  • plasma
  • blood
  • half
  • 20-25%
  • 625ml
  • 125ml
  • FF = GFR x RPF
  • FF = GFR / RPF

Pregunta 8

Pregunta
The filtered load is the amount of substance filtered per minute. Choose the best equation for filtered load.
Respuesta
  • FL = GFR x Ps
  • FL = GFR x Cs
  • FL = Ps / GFR
  • FL = Cs / GFR

Pregunta 9

Pregunta
Choose all the molecules that are ONLY ever reabsorbed in the nephron's tubules. (In a healthy person.)
Respuesta
  • Water
  • Glucose
  • Na+
  • Cl-
  • Ca++
  • dopamine
  • bile salts
  • K+

Pregunta 10

Pregunta
Which of these molecules can be both secreted and reabsorbed in the nephron's tubules?
Respuesta
  • K+
  • NH3
  • H+
  • HCO3
  • urea
  • Na+
  • Water

Pregunta 11

Pregunta
PAH (p-aminohippurate) is only ever secreted in the nephron, and this secretion is always active.
Respuesta
  • True
  • False

Pregunta 12

Pregunta
Choose the incorrect statement about the proximal convoluted tubule.
Respuesta
  • It is the site of bulk reabsorption—66% of water, Na+, and Cl- are reabsorbed.
  • All of glucose and amino acids reabsorbed in it.
  • Half of urea is reabsorbed in it.
  • Organic acids and drugs are secreted into it.
  • 90% of HCO3 is reabsorbed in it.

Pregunta 13

Pregunta
There are 4 sites of Na+ reabsorption: 66% of Na+ is reabsorbed in the [blank_start]PCT(proximal convoluted tubule)[blank_end]. 25% of Na+ is reabsorbed in the [blank_start]TAL(Thick ascending limb)[blank_end]. 5% of Na+ is reabsorbed in the [blank_start]DCT(distal convoluted tubule)[blank_end]. 3% of Na+ is reabsorbed in the [blank_start]CD(collecting duct)[blank_end].
Respuesta
  • proximal convoluted tubule
  • thick ascending limb
  • thin ascending limb
  • distal convoluted tubule
  • collecting duct
  • convoluted duct

Pregunta 14

Pregunta
Choose the correct statement about transporters.
Respuesta
  • Na+ is transported by luminal membrane transporters in tight epithelium.
  • Na+ is transported by channels in leaky epithelium.
  • Glucose uses Na+ dependent transporters (SGLT1 or SGLT2) to move into the cell from the filtrate.
  • Glucose uses Na+ dependent transporters, GLUT1 or GLUT 2, to move into the blood out of the cell.

Pregunta 15

Pregunta
The normal filtered load of glucose should be 0.
Respuesta
  • True
  • False

Pregunta 16

Pregunta
In leaky epithelium such as the [blank_start]PCT[blank_end], the water permeability is high. Water can be reabsorbed via the paracellular or transcellular pathway. [blank_start]With[blank_end] ADH, aquaporins AQP1 and AQP2 move into the [blank_start]apical[blank_end] membrane to move water into the cell. AQP3 and AQP4 move water out of the cell. In tight epithelium such as the [blank_start]collecting duct[blank_end], water permeability is low. The only aquaporin used is [blank_start]AQP2[blank_end].
Respuesta
  • PCT
  • collecting duct
  • With
  • Without
  • apical
  • basolateral
  • AQP2
  • AQP1
  • AQP3
  • AQP4

Pregunta 17

Pregunta
The loop of Henle in the [blank_start]juxtamedullary[blank_end] nephrons is crucial for production of concentrated urine, i.e. it is important for [blank_start]absorbing[blank_end] the water and NaCl. The thin descending limb removes [blank_start]water[blank_end] (i.e. it is leaky) while the thick ascending limb removes [blank_start]NaCl[blank_end](i.e. it is tight).
Respuesta
  • juxtamedullary
  • cortical
  • reabsorbing
  • excreting
  • water
  • naCl
  • NaCl
  • water

Pregunta 18

Pregunta
Which of these are appropriate average values for total body water?
Respuesta
  • Males - 42L, Females - 38.5L
  • Males - 32L, Females - 28.5L
  • Males - 52L, Females - 48.5L

Pregunta 19

Pregunta
Typical NaCl concentration in the body (ICF/ECF) is 145mM. This means typical fluid osmolarity is around:
Respuesta
  • 145mosmol/L
  • 290mosmol/L
  • 72.5mosmol/L

Pregunta 20

Pregunta
The kidneys are crucial for maintaining body water balance. If a person's water intake was 2400mL in a day, what could be a reasonable value for water excretion contribution by the kidneys?
Respuesta
  • ~400mL
  • ~2000mL
  • ~1400mL

Pregunta 21

Pregunta
Reabsorption of water in the PCT is driven by Na+ reabsorption and is isotonic.
Respuesta
  • True
  • False

Pregunta 22

Pregunta
Primary urine in the PCT is [blank_start]isotonic[blank_end]. Due to water reabsorption in the tDLH, it becomes [blank_start]hypertonic[blank_end]. It turns [blank_start]hypotonic[blank_end] due to Na+ reabsorption in the TAL, and can become hypertonic again in the [blank_start]collecting duct[blank_end] during [blank_start]anti-diuresis[blank_end].
Respuesta
  • isotonic
  • hypertonic
  • hypotonic
  • collecting duct
  • DCT
  • anti-diuresis
  • diuresis

Pregunta 23

Pregunta
Choose the incorrect statement.
Respuesta
  • Water moves to areas of low osmolarity
  • Dehydration increases ECF osmolarity due to water loss, and water moves out of the ICF (shrinks cells)
  • Hyperhydration decreases ECF osmolarity due to water gain, and water moves into the ICF (cells swell)
  • ADH alters the permeability of the collecting duct

Pregunta 24

Pregunta
With ADH, the collecting duct is relatively permeable to water and 8% of filtered water can be excreted.
Respuesta
  • True
  • False

Pregunta 25

Pregunta
Choose the incorrect statement about isosmotic losses.
Respuesta
  • Isosmotic losses can be things like diarrhoea, vomiting, and bleeding
  • No ECF/ICF osmolarity gradient will be produced
  • Volume loss is restricted to ICF

Pregunta 26

Pregunta
Choose the incorrect statement about isosmotic gains.
Respuesta
  • Isosmotic gains can be caused by renal failure
  • ECF volume increases
  • Cells will be affected

Pregunta 27

Pregunta
There are two systems for regulating fluid gains and losses. An osmotic change (just water loss/gain) will be [blank_start]spread between the ICF and ECF[blank_end]. This effects cells. It can be corrected with [blank_start]ADH release[blank_end] changes, which is a [blank_start]fast[blank_end] response system. An isosmotic change will be [blank_start]limited to the ECF[blank_end]. This causes changes to blood pressure and volume which the heart can cope with. It can be corrected via [blank_start]Na+ excretion/retention[blank_end], which is a [blank_start]slow[blank_end] response system.
Respuesta
  • spread between the ICF and ECF
  • limited to the ECF
  • ADH release
  • Na+ excretion/retention
  • fast
  • slow
Mostrar resumen completo Ocultar resumen completo

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