Pregunta 1
Pregunta
A system when b1 = b2 = ··· = bm = 0 is called
Respuesta
-
Homogeneous
-
Non-homogeneous
Pregunta 2
Pregunta
A system is said to be homogeneous when b1 = b2 = ·· ·= bm = 0
Pregunta 3
Pregunta
Homogeneous systems always have at least one solution called “the trivial solution”
Pregunta 4
Pregunta
Homogeneous systems don't have solutions
Pregunta 5
Pregunta 6
Pregunta
Number of columns
Pregunta 7
Pregunta
( 5 6 7 8 ) is a 1 x 4 matrix
Pregunta 8
Pregunta
( 5 6 7 8 ) is a 4 x 1 matrix
Pregunta 9
Pregunta
( 5 6 7 8 9 ) is a 5 x 1 matrix
Pregunta 10
Pregunta
( 5 6 7 8 9 ) is a 1 x 5 matrix
Pregunta 11
Pregunta
The matrix 1
2
3
4
Is a 1 x 4 matrix
Pregunta 12
Pregunta
The matrix 1
2
3
4
Is a 4 x 1 matrix
Pregunta 13
Pregunta
What is the order of The matrix 1
2
3
4
Pregunta 14
Pregunta
Two matrices A and B are equal if and only if:
Respuesta
-
Both have the same dimension say m x n
aij = bij for all i,j.
-
Both have the same dimension say m x n
a = bij for all i,j.
-
Both have the same dimension say m x n
aij = bij for some i,j.
-
Both have the same dimension say m x n
aij = b for all i,j.
Pregunta 15
Pregunta 16
Pregunta
Matrix Multiplication Is Not Commutative
Pregunta 17
Pregunta
Matrix Multiplication Is Commutative
Pregunta 18
Pregunta
Matrix Multiplication Is Not Associative
Pregunta 19
Pregunta
Matrix Multiplication Is Associative
Pregunta 20
Pregunta
What does it mean for matrix multiplication to be associative ?
Respuesta
-
ABC = A(BC) = (AB)C
-
ABC = A(BC) = ABC
-
ABC = CBA
-
ABC = CBA = CAB = BCA
Pregunta 21
Pregunta
An n × n matrix is diagonal when: aij =0 for i /= j
Pregunta 22
Pregunta
An n × n matrix is diagonal when: aij =0 for i = j
Pregunta 23
Pregunta
An upper triangular matrix is any n × n matrix where
Respuesta
-
aij =0 where i /= j
-
aij =0 wherei > j
-
aij =0 where i > i
Pregunta 24
Pregunta
lower triangular matrix has:
Respuesta
-
aij =0 where j > i
-
aij =0 where j \> i
-
aij =0 where j = i
Pregunta 25
Pregunta
If the n x n matrix A is invertible then
Respuesta
-
AB = In = BA
-
AB = In = BA-1
-
AB = BA
-
AB = In = B-1A-1