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Creado por Mia Parker
hace casi 2 años
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Pregunta | Respuesta |
Frame of Reference | A framework that is used for the observation and mathematical description of physical phenomena and the formulation of physical laws. |
1. Dynamics 2. Kinematics | 1. explains the causes of motion 2. Describes motion |
Distance | How far an object moves/total ground it covers (scalar quantity) |
Scalar Quantity | Defined by magnitude or volume |
Displacement | (x) Distance and direction with respect to the origin |
Vector Quantity | Requires magnitude and direction |
Average Speed | Distance per time |
Equation for speed | S=(d/t) |
Average Velocity (v) | Displacement per time |
Change in Displacement Formula | ∆x=(xf)-(x0) |
Equation for Velocity | V=((∆x)/t) |
Constant Displacement | ∆x=0, v=0 |
Constant Velocity | Linear relationship where x changes with respect to time. Positive velocity moves forward, up, or right. Negative velocity moves backward, down, or left. |
Displacement Formula | ∆x=v*t |
Acceleration (a) | A change in velocity over a time interval. |
When is an object speeding up? | When velocity and acceleration have the same sign. |
When is an object slowing down? | When velocity and acceleration have opposite signs. |
Equation for Acceleration | a=((∆v)/t) |
Equation for Change in Velocity | ∆v=(vf)-(v0) |
Constant Acceleration | The velocity changes regularly with respect to time. Since the velocity is changing, the slope must change, causing for a curved line (parabolic relationship). |
What does the slope of a velocity graph tell you? | The acceleration of that object. *remember that you can solve by using the units to figure out the relationship (velocity vs time graph: v=m/s t=s thus, acceleration is v/t = m/s^2) |
What does the area under the curve of a velocity graph tell you? | The displacement of an object. |
A graph that is concave up has (...) acceleration | Positive |
A graph that is concave down has (...) acceleration | Negative |
What equation uses... V0 ∆x 1/2 Vf t | ∆x=.5((v0)+(vf))t |
What equation uses... V0 t a t^2 ∆x .5 | ∆x=((v0)t) + .5at^2 |
What equation uses... a Vf t V0 | Vf=(v0) + at |
What equation uses... V0^2 2 Vf^2 ∆x a | Vf^2=(v0^2)+2a∆x |
Free Fall | Object acts under the influence of gravity alone. Assumes air resistance is negligible. Gravity is a constant force. |
What is the acceleration due to gravity? | g=-9.8 m/s^2 |
For free fall, what can you do to the equations to constant acceleration? | Substitute -9.8 in for a. Substitute ∆y in for ∆x (height). |
What is always important to remember of the x and y planes? | They are independent of each other. |
Horizontal Component (x) | Constant Velocity |
Vertical Component (y) | Constant acceleration due to the force of gravity |
Why is the path of a projectile always a parabola? | ∆x remains constant (constant velocity) while ∆y changes exponentially (due to acceleration) |
Constant Velocity Trigonometric Equation | Vx=(V0)*cos(Θ) |
Initial Velocity Trigonometric Equation | V0y=(V0)*sin(Θ) |
X-Motion | Constant velocity. Definition of Velocity Equation: ∆x=(Vx)t |
Y-Motion | Constant acceleration due to gravity. Free fall equations. |
What is the only similar thing between the x and y planes? | time |
Range (∆x) | Horizontal displacement. It is dependent on the launch velocity and angle (Vx) |
What angle allows for maximum range? | 45º |
Complimentary Angles | Sum of two angles is 90º. |
Velocity | displacement over time dis/time |
Acceleration | Change in velocity / Time a = Δv/Δt simple ex.: a= Vf-Vi/t |
Horizontal Variables | |
Horizontal Kinematic Equations | |
Vertical Variables | |
Vertical Kinematic Equations | |
Projectile | An object that is thrown or launched (up or down or onto) |
Parabola | The shape of a projectile's trajectory |
Trajectory | The path an object follows |
YOU GOT THIS !!!! | - https://www.youtube.com/watch?v=3BE33aceKvE&list=PLzTqBfZ51K25epbid3AD8QsEneV39aiZJ&index=11 - https://www.albert.io/ap-physics-1/overview http://wsapphysics.weebly.com/quizlet.html |
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