824105
| Pregunta | Respuesta |
| Reaction of NaF with concentrated sulfuric acid (H2SO4) | - NaF(s)+H2SO4(aq) --> NaHSO4(s) +HF(g) - Misty fumes as gas comes into contact with moisture in air -HF not strong enough reducing agents to reduce sulfuric acid so not a redox |
| Reaction of NaCl with concentrated sulfuric acid (H2SO4) | - NaCl(s)+H2SO4(aq) --> NaHSO4(s) +HCl(g) - Misty fumes as gas comes into contact with moisture in air -HCl not strong enough reducing agents to reduce sulfuric acid so not a redox |
| First reaction with NaBr and concentrated sulfuric acid (H2SO4) | NaBr(s) + H2So4(aq) --> NaHSO4(s) +HBr (g) - misty fumes of hydrogen bromide seen |
| Second (redox) reaction that occurs when NaBr is reacted with concentrated sulfuric acid (H2SO4) | HBr is a stroger reducing agent than HCl so can react with H2SO4 in redox reaction: 2HBr(aq) + H2SO4(aq) --> Br2(g) + SO2(g) + 2H2O (l) - sulfur goes from ox. state of +6 to +4 - Br goes from ox. state of -1 to 0 - choking fumes of SO4 -Orange Br2 fumes |
| First reaction of NaI with concentrated sulfuric acid (H2SO4) | NaI(s) + H2SO4(s) --> NaHSO4(s) + HI (g) |
| Redox reaction that occurs in the inital reaction of NaI and concentrated sulfuric acid (H2SO4) | 2HI(g) + H2SO(aq) --> I2(s) + SO2(g) + 2H2O(l) -sulfur ox. state +6 to +4 -Iodine ox. state -1 to 0 -reaction occurs because HI produced in initial reaction reduces H2SO4 |
| Second redox reaction between NaI and H2SO4 | 6HI(g)+SO2(g) --> H2S(g) +3I2(s)+2H2O(l) - HI keeps reducing So2 and H2S - Sulfuer ox. state +4 to -2 -I ox. state from -1 to 0 |
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