C1 key points

Pregunta	Respuesta
Surds	√ xy = √ x + √ y √ x/y = √ x /√ y a√ x + b √ x = (a + b) √ x √ x+y = √ x + √ y
rationalising	1 / √ a = (1) x (√ a) / (√ a) x (√ a) 1/ a + √ b = 1 x (a - √ b) / (a + √ b) x (a - √ b)
indicies	a^m x a^n = a^n+m a^m/a^n = a^m-n (a^m)^n = a^mn a^0 = 1 a^-n = 1 / a^n a^1/n = n√ a a^m/n = (n√ a)^m
quadratic functions	f(x)= ax^2 +bx +c, discriminant b^2 - 4ac F(x) = 0 b^2 -4ac >0 two real roots b^2 -4ac =0 two real equal roots b^2 -4ac <0 two unreal roots
the quadratic formula	x = -b ± (b^2 -4ac) / 2a
sketching quadratics	y intercept, x = 0 x intercept, y = 0 maximum/minimum by completing the square
transformations	y = F(x) + a, y axis by +a y = F(x + a), x axis by -a y = aF(x), y axis by xa y = F(ax), x axis by x1/a
coordinate geometry	gradient = [y2-y1]/[x2-x1] distance = √([x2-x1]^2 + [y2-y1]^2) y =mx+c y-b=m(x-a) co-ord (y-y1) / (y2-y1) = (x-x1) / (x2-y1) mid point [ (x1+x2) / 2 , (y1 + y2) / 2 ] parallel m = m, perpendicular m1 x m2 = -1
sequences	a + (n-1)d Sn = n/2 [2a + (N-1)d]
differentiation	y = f(x) dy/dx = f'(x) ax^n = anx^n-1 gradient of tangent to a curve = dx
integration	∫ax^n = ax^n+1 / n +1

Resumen del Recurso

	Creado por Saavik Hipkins hace alrededor de 7 años