Kerrin _
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Includes pressure changes in gaseous systems, temperature, concentration and addition of a catalyst.

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Kerrin _
Creado por Kerrin _ hace alrededor de 8 años
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NCEA Lvl 2 - Changes to Systems at Equilibrium

Pregunta 1 de 6

1

What effect does increasing the pressure of a closed gaseous system at equilibrium have on the state of equilibrium if the forward reaction creates 2 mol and the reverse reaction creates 3 mol?

Selecciona una de las siguientes respuestas posibles:

  • No effect

  • The forward reaction becomes favored

  • The reverse reaction becomes favored

Explicación

Pregunta 2 de 6

1

The addition of a catalyst to a system at equilibrium will increase the concentration of the products of the forward reaction.

Selecciona uno de los siguientes:

  • VERDADERO
  • FALSO

Explicación

Pregunta 3 de 6

1

An increase in temperature will do what to a system at equilibrium?

Selecciona una de las siguientes respuestas posibles:

  • Shift the equilibrium to favor the endothermic reaction.

  • Change the Kc value (equilibrium constant)

  • Increase the concentration of products produced by the endothermic reaction

  • All of the above

Explicación

Pregunta 4 de 6

1

An increase in the concentration of the products results in an increase in the value of Kc

Selecciona uno de los siguientes:

  • VERDADERO
  • FALSO

Explicación

Pregunta 5 de 6

1

Le Chatelier's principle states that when stress is placed on a system at equilibrium the system will work in such a way that reduces this stress.

Selecciona uno de los siguientes:

  • VERDADERO
  • FALSO

Explicación

Pregunta 6 de 6

1

Increasing the concentration of A will do what to the following system at equilibrium?
A + B <-----> C + D

Selecciona una de las siguientes respuestas posibles:

  • The system will shift to favor the reverse reaction so that the concentration of B will become equal to A

  • The system will shift to favor the forward reaction to reduce the increase in concentration of A

  • The system will not be affected

  • The Kc constant will decrease

Explicación