Mer Scott
Test por , creado hace más de 1 año

• Identify the inheritance patterns of sex-linked genes. • Explain that linked genes show non-independent assortment. • Explain that crossing over leads to recombination of linked genes. • Discuss how recombination frequencies are used to map genes.

44
2
0
Mer Scott
Creado por Mer Scott hace más de 7 años
Cerrar

L25 Sex-linkage and recombination of linked genes

Pregunta 1 de 11

1

Which parents determines the sex of the offspring?

Selecciona una de las siguientes respuestas posibles:

  • Mother

  • Father

Explicación

Pregunta 2 de 11

1

A male fruit fly is white eyed, which is recessive, and an X-linked gene. What term would we use to describe its genotype?

Selecciona una de las siguientes respuestas posibles:

  • Homozygous recessive

  • Heterozygous recessive

  • Hemizygous recessive

Explicación

Pregunta 3 de 11

1

A male fruit fly carries an X chromosome with a white eyed allele, and is mated with a female homozygous for red eye alleles. Which statement would be true?

Selecciona una de las siguientes respuestas posibles:

  • All offspring will have white eyes.

  • All male offspring will have white eyes.

  • All daughters will be heterozygotes.

Explicación

Pregunta 4 de 11

1

A colour blind male mates with a homozygous non colourblind female. Which statements are true?

Selecciona una o más de las siguientes respuestas posibles:

  • All sons are colourblind.

  • None of the sons will be colourblind.

  • All daughters will be carriers.

  • There is a 50% chance one of the children will be colourblind.

  • If one of the daughters has offspring with a non-colourblind male, there is a 50% chance that their son will be colourblind.

Explicación

Pregunta 5 de 11

1

You perform a dihybrid cross between a heterozygote and a homozygous recessive individual. Instead of the expected 1:1:1:1 ratio, the parental types are far more common and only a small ratio of the offspring are recombinants. What can you conclude and why?

Selecciona una de las siguientes respuestas posibles:

  • The genes did not assort independently because they are linked on the same chromosome.

  • The genes did not assort independently because there was a failure to separate during anaphase I.

  • The genes being tested for actually do not segregate and are alleles.

Explicación

Pregunta 6 de 11

1

Theoretically meiosis should cause all to have the type if genes being observed are .

Arrastra y suelta para completar el texto.

    gametes
    parental
    linked

Explicación

Pregunta 7 de 11

1

Which statement best describes recombinant frequency?

Selecciona una de las siguientes respuestas posibles:

  • The number of times recombination occurs during meiosis.

  • The proportion of recombinant gametes that are produced.

  • The number of recombinant individuals in a population.

Explicación

Pregunta 8 de 11

1

The larger the distance between two genes the less likely a chiasmata will be formed between them.

Selecciona uno de los siguientes:

  • VERDADERO
  • FALSO

Explicación

Pregunta 9 de 11

1

A small recombinant frequency indicates a small distance between genes.

Selecciona uno de los siguientes:

  • VERDADERO
  • FALSO

Explicación

Pregunta 10 de 11

1

What is the maximum recombination frequency?

Selecciona una de las siguientes respuestas posibles:

  • 100%

  • 50%

  • 49.9%

Explicación

Pregunta 11 de 11

1

Choose the correct statements about genetic map units.

Selecciona una o más de las siguientes respuestas posibles:

  • They are arbitrary.

  • They are also known as cM, centimacrometres.

  • They are also known as cM, centimorgans.

  • The number of map units can be calculated by multiplying the recombinant frequency by 100.

  • The number of map units can be calculated by dividing the recombinant frequency by 100.

Explicación

Anterior
Siguiente