444202
Description
Flashcards by Carlos Martínez, updated more than 1 year ago
|
Created by Carlos Martínez
almost 11 years ago
|
|
| Question | Answer |
| y = f(x) + g(x) | y´ = f´(x) + g´(x) |
| y = f(x) · g(x) | y´ = f´(x)·g(x) + f(x)·g´(x) |
| y = f(x) / g(x) | y´ = (f´(x)·g(x) + f(x)·g´(x))/[g(x)]^2 |
| y = K | y´ = 0 |
| y = x | y´ = 1 |
| y = K · x | y´ = K |
| y = K · f(x) | y´ = K · f´(x) |
| y = 1 / x | y´= - 1 / x^2 |
| y = x^n | y´= n · x^(n-1) |
| y = (x)^1/2 | y´ = 1 / (2 · x^1/2) |
| y = (x)^1/n | y´ = 1 / (n · [x^(n-1)]^1/n) |
| y = a^x | y= a^x · ln a |
| y = e^x | y´ = e^x |
| y = ln x | y´ = 1 / x |
| y = log(a) x | y´ = 1 / (x · ln a) |
| y = sen x | y´ = cos x |
| y = cos x | y´ = - sen x |
| y = tag x | y´ = (sec x)^2 = 1 / (cos x)^2 = 1 + (tag x)^2 |
| y = arc sen x | y´ = 1 / (1 - x^2)^1/2 |
| y = arc cos x | y´ = - 1 / (1 - x^2)^1/2 |
| y = arc tag x | y´= 1 / (1 + x^2) |
Want to create your own Flashcards for free with GoConqr? Learn more.