4820430
| Question | Answer |
| csc x= | 1/sin x |
| sec x= | 1/cos x |
| cot x= | 1/tan x |
| tan x= | sin x /cos x |
| cot x= | cos x /sin x |
| sin^2 x +cos^2 x = | 1 |
| tan^2 x +1 = | sec^2 x |
| 1 + cot^2 x= | csc^2 x |
| sin (-x)= | -sin x |
| cos (-x)= | cos x |
| tan (-x)= | -tan x |
| csc (-x)= | -csc x |
| sec (-x) = | sec x |
| cot (-x) = | -cot |
| sin (a+b) = | sin a cos b +sin b cos a |
| sin (a-b)= | sin a cos b - sin b cos a |
| cos (a+b)= | cos a cos b - sin a sin b |
| cos (a-b) = | cos a cos b + sin a sin b |
| tan (a+b) = | tan a +tan b / 1-tan a tan b |
| tan (a-b)= | tan a - tan b / 1+ tan a tan b |
| sin (2x)= | 2 sin x cos x |
| cos (2x) = | cos ^2 x - sin^2 x |
| tan (2x) = | 2 tan x / 1-tan^2 x |
| sin (x/2) = | +-√(1-cos x)/2 |
| cos (x/2)= | +-√(1+cos x)/2 |
| tan (x/2)= | 1-cos x/ sin x =sin x / 1+cos x |
Want to create your own Flashcards for free with GoConqr? Learn more.