Created by Caitlyn Jones
almost 7 years ago
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Question | Answer |
A (aq) + B (aq) → AB (aq) How do you find the effect of [A]? What about [B]? | Change [A], keep [B] and temp constant. Change [B], keep [A] and temp constant |
What is the Rate equation? What do each of the letters stand for? | Rate = k[A]ᵃ[B] k = Rate constant a = Order with respect to [A] b = Order with respect to [B] |
What is meant by the term "Order"? | Power to wi=hich a concentration must be raised to get the correct change in rate. Can only be found by experiment. |
What order is this graph? | Second |
What order is this graph? | Zero |
What order is this graph? | First |
How would you work out the difference between first and second order graphs when it is concentration & time? | There is a constant half-life for first order graphs, not with second. |
Which is the rate determining step (RDS)? | The slow one. |
What is the Arrehenius Equation and what do the letters stand for? What are the units? | k = Ae⁻ᴱᵃ/ᴿᵀ A = Frequency factor - Units depend on rate e = Mathematical term - No units Ea = Activation energy - kJ/mol R = Constant - J/mol T = Temperature - Kelvins |
What does e⁻ᴱᵃ/ᴿᵀ mean? | The fraction of particles in a gas that have the Ea or above. |
What are the reactants of an "Iodine Clock" and what are they used for? | Reactants:- Iodide ions - must be produced Acidified hydrogen peroxide - Oxidises iodide ions. |
What are the products of an "Iodine Clock"? | Iodine and Water |
What is used to test for iodine? What is produced? | Starch is used to detect iodine, a blue/black colour is produced. |
What problem arises during this reaction, and how do you overcome it? | Blue/black colour is instantly seen. Sodium thiosulfate is used to stop the starch producing the blue/black colour. Once it is all used up, the next molecule of iodine will produce the blue/black colour. The quicker it is produced, the faster the rate. |
Can you provide equations for these reactions? | 2I⁻ → I₂ + 2e⁻ 2S₂O₃²⁻ → S₄O₆²⁻ + 2e⁻ I₂ +2S₂O₃²⁻ → 2I⁻ + S₄O₆²⁻ |
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