Created by Zaid Ciddiqui
almost 7 years ago
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Question | Answer |
Arithmetic progressions | > nth term from starting: a+(n-1)d > nth term from last: l-(n-1)d > d = Tn-a/n-1 >Sn = n/2[2a+(n-1)d] >Sn = n/2[a+l] > Sum of the first natural numbers: n(n+1)/2 |
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