Created by Alessandro Algar
over 6 years ago
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Question | Answer |
Frequency is the inverse of the period | f = \(\frac{1}{T}\) |
The wave equation | V = f \(\lambda\) |
Intensity = | \(\frac{Power}{Area}\) |
Intensity is | ∝ \((Amplitude)^2\) |
Refractive Index = | \(\frac{Cmedium1}{Cmedium2}\) = \(\frac{sini}{sinr}\) |
Refractive Index of material | n=\(\frac{Cvacuum}{Cmaterial}\) |
Snell's Law | n1\(\sin\)\(\theta\)1 = n2\(\sin\)\(\theta\)2 |
Line Separation = | \(\frac{1}{lines/metre}\) |
Fringe Spacing | w = \(\frac{λD}{s}\) |
Incident light wavelength | nλ = d\(\sin\)\(\theta\) |
Standing Waves: String experiment Equation 1 | Mass/unit length: \(\mu\) = \(\frac{M}{L}\) |
Equation 2 | Tension: T = mg |
Equation 3 | Wavelength given as: \(\lambda\) = 2l |
Equation 4 | Frequency: f = \(\frac{1}{2l}\)\(\sqrt {\frac{T}{μ}}\) |
Equation 5 | v = \(\sqrt {\frac{T}{μ}}\) |
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