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CHEMISTRY C1 7

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Dérivées

Description

Flashcards on Dérivées, created by Leonard Euler on 20/12/2014.

Flashcards by Leonard Euler, updated more than 1 year ago

	Created by Leonard Euler over 10 years ago

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Resource summary

Question	Answer
$\dfrac{d}{dx} c$	$0$
$\dfrac{d}{dx} x$	$1$
$\dfrac{d}{dx} x^2$	$2x$
$\dfrac{d}{dx} x^3$	$3x^2$
$\dfrac{d}{dx} x^k$	$k\cdot x^{k-1}$
$\dfrac{d}{dx} \dfrac{1}{x}$	$-\dfrac{1}{x^2}$
$\dfrac{d}{dx} \sqrt{x}$	$\dfrac{1}{2\sqrt{x}}$
$(\lambda\cdot u)'$	$\lambda\cdot u'$
$(u+v)'$	$u'+v'$
$(u\cdot v)'$	$u'\cdot v+u\cdot v'$
$\Big(\dfrac{1}{u}\Big)'$	$-\dfrac{u'}{u^2}$
$\Big(\dfrac{u}{v}\Big)'$	$\dfrac{u'\cdot v-u\cdot v'}{v^2}$
$(u\circ v)'$	$(u' \circ v)\cdot v'$
$(\sqrt{u})'$	$\dfrac{u'}{2\sqrt{u}}$
$(u^k)'$	$k\cdot u^{k-1}\cdot u'$
$\dfrac{d}{dx} \sin{x}$	$\cos{x}$
$\dfrac{d}{dx} \cos{x}$	$-\sin{x}$
$\dfrac{d}{dx} \tan{x}$	$1+\tan^2{x}=\dfrac{1}{\cos^2{x}}$
$(\sin{u})'$	$u'\cdot \cos{u}$
$(\cos{u})'$	$-u'\cdot \sin{u}$
$(\tan{u})'$	$u'\cdot(1+\tan^2{u})=\dfrac{u'}{\cos^2{u}}$
$\dfrac{d}{dx} e^x$	$e^x$
$\dfrac{d}{dx} \ln{x}$	$\dfrac{1}{x}$
$(e^u)'$	$u'\cdot e^u$
$(\ln{u})'$	$\dfrac{u'}{u}$

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