Created by mariaahbanu
about 9 years ago
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Question | Answer |
l | r x Ө |
radian | π/180 x degree |
degree | 180/π x radian measure |
cos^2 x + sin^2 x | 1 |
1 + tan^2 x | sec^2x |
1 + cot^2 x | cosec^2x |
cos (2nπ + x) | cosx |
sin (2nπ + x) | sinx |
sin(-x) | -sinx |
cos(-x) | cosx |
cos(x+y) | cosxcosy-sinxsiny |
cos(x-y) | coxcosy+sinxsiny |
cos(π/2-x) | sinx |
sin(π/2-x) | cosx |
sin(x+y) | sinxcosy+cosxsiny |
sin(x-y) | sinxcosy-cosxsiny |
cos (π/2 + x) | -sinx |
sin (π/2 + x) | cosx |
cos (π – x) | –cos x |
sin (π – x) | sin x |
cos (π + x) | – cos x |
sin (π + x) | –sin x |
cos (2π – x) | cos x |
sin (2π – x) | –sin x |
tan(x+y) | tanx+tany / 1-tanxtany |
tan(x-y) | tanx-tany / 1+tanxtany |
cot(x+y) | cotxcoty-1 / coty+cotx |
cot(x-y) | cotxcoty+1 / coty-cotx |
cos2x | :cos^2 x - sin^2 x :2cox^2 x - 1 :1-2sin^2 x :1-tan^2 x / 1+tan^2 x |
sin2x | :2sinxcosx :2tanx / 1+tan^2 x |
tan2x | 2tanx / 1-tan^2 x |
sin3x | 3sinx - 4sin^3 x |
cos3x | 4cos^3 x - 3cosx |
tan3x | 3tanx-tan^3 x / 1-3tan^2 x |
cosx+cosy | 2cosx+y/2 cosx-y/2 |
cosx-cosy | -2sinx+y/2 sinx-y/2 |
sinx+siny | 2sinx+y/2 cosx-y/2 |
sinx-siny | 2cosx+y/2 sinx-y/2 |
2cosxcosy | cos(x+y) + cos(x-y) |
-2sinxsiny | cos(x+y) - cos(x-y) |
2sinxcosy | sin(x+y) + sin(x-y) |
2cosxsiny | sin(x+y) - sin(x-y) |
sinx = 0 | →x = nπ |
cosx = 0 | →x = (2n+1)(π/2) |
sin x = sin y | ⇒ x = nπ + (–1)^n y |
cos x = cos y | ⇒ x = 2nπ ±y |
tan x = tan y | ⇒ x = nπ + y |
2sin^2 X/2 | 1 - cosx |
2cos^2 x/2 | 1 + cosx |
tan θ/2 | 1-cosθ / sinθ |
sin(A+B) sin(A-B) | :sin^2 A - cos^2 B :cos^2 B - cos^2 A |
cos(A+B) cos(A-B) | :cos^2 A - sin^2 B :-sin^2 A + cos^2 B |
tan(A+B) tan(A-B) | tan^2 A-tan^2 B / 1-tan^2 A tan^2 B |
Sine Formula | sinA/a = sinB/b = sinC/c = k |
Cosine Formula | :a^2 = b^2 + c^2 -2bccosA :b^2 = c^2 + a^2 -2cacosB :c^2 = a^2 + b^2 -2abcosC :CosA = (b^2 +c^2 -a^2)/2bc :CosB = (c^2 +a^2 -b^2)/2ac :CosC = (a^2 +b^2 -c^2)/2ab |
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