Question | Answer |
Standard Form | \[Ax+By=C\] |
Slope | M=\[\frac{y_2-y_1}{x_2-x_1}\] |
Slope-Intercept Form | \[y=mx+b\] |
Point-Slope Form | \[y-y_1=m(x-x_1)\] |
Distance on a Number Line | D=\[|a-b|\] |
Distance on a Coordinate Plane | D=\[\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] |
Distance in Space (3D) | D=\[\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}\] |
Distance Arc Length | L=\[\frac{N}{360}·2\pi·r\] |
Midpoint on a Number Line | M=\[\frac{a+b}{2}\] |
Midpoint on a Coordinate Plane | M=\[\frac{x_1+x_2}{2},\]\[\frac{y_1+y_2}{2}\] |
Midpoint in Space (3D) | M=\[\frac{x_1+x_2}{2},\]\[\frac{y_1+y_2}{2},\]\[\frac{z_1+z_2}{2}\] |
Perimeter of a Square | P=\[4s\] (s=side) |
Perimeter of a Rectangle | P=\[2l+2w\] (l=length, w=width) |
Circumference of a Circle | C=\[2\pi·r,\pi·d\] |
Area of a Square | A=\[s^2, lw\] |
Area of a Rectangle | A=\[lw, bh\] |
Area of a Parallelogram | A=\[bh\] |
Area of a Trapezoid | A=\[\frac{1}{2}h(b_1+b_2)\] |
Area of Rhombus | A=\[\frac{1}{2}d_1d_2, bh\] |
Area of Triangle | A=\[\frac{1}{2}bh\] |
Area of Regular Polygon | A=\[\frac{1}{2}Pa\] |
Area of a Circle | A=\[\pi·r^2\] |
Area of Sector of a Circle | A=\[\frac{N}{360}\·pi·r^2\] |
Quadratic Formula | \[\frac{-b±√b^2-4ac}{2a}\] |
Lateral Surface Area of Prism | L=\[Ph\] |
Lateral Surface Area of a Cylinder | L=\[2\pi·r·h\] |
Lateral Surface Area of a Pyramid | L=\[\frac{1}{2}Pl\] |
Lateral Surface Area of a Cone | L=\[\pi·r·l\] |
Total Surface Area of a Sphere | SA=\[4\pi·r^2\] |
Total Surface Area of a Hemisphere | SA=\[3\pi·r^2\] |
Volume of a Pyramid | V=\[\frac{1}{3}Bh\] |
Volume of a Rectangular Prism | V=\[Bh\] |
Volume of a Right Circular Cylinder | V=\[2\pi·r^2+2\pi·r·h\] |
Volume of a Right Circular Cone | V=\[\frac{1}{3}·pi·r^2·h\] |
Volume of a Sphere | SA=\[\frac{3}{4}·pi·r^3\] |
Surface Area of a Regular Prism or Cylinder (2-based) | SA= \[Ph+2B\] *If you are finding the surface area of a cylinder, replace P (perimiter) with Circumfrance. |
Surface Area of a Regular Pyramid or Cone (1-based) | A=\[\frac{1}{2}Pl+B\] *If you are finding the surface area of a cone, replace P (perimiter) with Circumfrance **l= slanted height |
Pythagorean Theorem | \[a^2+b^2=c^2\] |
\[\sin A=\]\[\frac{a}{c}\] | |
\[\cos A=\]\[\frac{b}{c}\] | |
\[\tan A=\]\[\frac{a}{b}\] | |
Sum of Degree Measures of the Interior Angles of a Polygon | \[180(n-2)\] (n=number of sides) |
Degree Measure of an Interior Angle of a Regular Polygon | \[\frac{180(n-2)}{n}\] |
⊥ | is perpendicular to |
|| | is parallel to |
≅ | is congruent to |
∼ | is similar to |
≈ | is approximately equal to |
∆ABC | triangle ABC |
∠ABC | angle ABC |
m∠ABC | the degree measure of angle ABC |
Circle O | circle with center point O |
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