Created by Marika Rutlin
over 8 years ago
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Question | Answer |
sin²x + cos²x | 1 |
1 + tan²x | sec²x |
1 + cot²x | cosec²x |
if a ∙b = 0 | then the lines are perpendicular |
when differentiating with respect to x then 4y² will become... | 8y dy dx |
5x + 1 (x – 1)(2x + 1)² expressed as partial fractions | A B C (x – 1)(2x + 1)(2x + 1)² |
sin 2A | 2sin A cos A |
cos 2A | cos²A –sin²A |
tan2A | 2tanA 1 – tan²A |
∫e^ax dx | e^ax + c a |
∫f'(x) dx f (x) | ln|f(x)| +c |
the modulus of a vector |a| | √x² + y² + z² |
r = p + λd | p is the position vector of a particular point on the line, λ is a scalar parameter, d is any vector parallel to the line (called a direction vector) |
acute angle in vectors cos ϴ = | a ∙b |a||b| |
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