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Created by Tasha Jones
over 12 years ago
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| Question | Answer |
| Commutative | P u Q = Q u P P n Q = Q n P |
| Associative | P u (Q u R) = (P u Q) u R P n (Q n R) = (P n Q) n R |
| Absorption | P u P = P P n P = P |
| Universal Set | P u E = E P n E = P |
| Empty Set | P u 0 = P P n 0 = 0 |
| Distributive | P n (Q u R) = (P n Q) u (P n R) P u (Q n R) = (P u Q) n (P u R) |
| De Morgan's | (P n Q)' = P' u Q' (P u Q)' = P' n Q' |
| Inclusion | P u (P n Q) = P P n (P u Q) = P P u (Q n P) # P |
| Complements | P u P' = E P n P' = 0 (P')' = P |
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