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762862
Core 3
Description
Mind Map on Core 3, created by abbeycropper on 16/04/2014.
Mind Map by
abbeycropper
, updated more than 1 year ago
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Created by
abbeycropper
over 10 years ago
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Resource summary
Core 3
Algebraic Fractions
Long division
The remainder theorem
Functions
The domain is the set on which the rule acts
The range is the set of results obtained by applying the rule
A function cannot be one to many
Composite functions
g(f(x)) = f first, then g
Inverse Functions
A function only as an inverse if it is a one to one
The domain of the original equation is the range of the inverse and vice versa
From an equation: 1) swap x's and y's 2) make y the subject
From a graph: Reflect it in the line y=x
Exponential and Log Functions
lnx is the inverse of eˣ
ln(eˣ) = x
If y=eˣ then dy/dx = eˣ
Numerical Methods
There is a change of sign in the interval [a,b], therefore a root lies between a and b
Transforming Graphs of Functions
The Modulus Function |a|
If y=|f(x)| draw the original graph and anything below the x axis is reflected in the x axis
If y=f|(x)| draw the positive half of the graph and reflect it in the y axis
f(x) +a - vertical up a units
f(x+a) - horizontal left a units
af(x) - stretch in y axis/multiply y co-ords by a
f(ax) - stretch in x axis/multiply x co-ords by 1/a
-f(x) - reflection in x axis
f(-x) - reflection in y axis
Differentiation
The Product Rule
If y=UV then dy/dx = Udv/dx + Vdu/dx
The Quotient Rule
If y=u/v then dy/dx = Vdu/dx - Udv/dx / v²
If y=eˣ then dy/dx = eˣ
If y=ef(x) then dy/dx = f'(x)ef(x)
If y=lnx then dy/dx = 1/x
Proof: If y=lnx x=eʸ dx/dy = eʸ dy/dx = 1/eʸ dy/dx = 1/x
If y=sinx then dy/dx = cosx
If y=cosx then dy/dx = -sinx
If y=tanx then dy/dx = sec²x
If y=cosecx dy/dx = -cosecxcotx
If y=secx dy/dx = tanxsecx
If y=cotx then dy/dx = -cosec²x
Trigonometry
secθ = 1/cosθ
cosecθ = 1/sinθ
cotθ = 1/tanθ
cosθ/sinθ = cotθ
tan²θ + 1 = sec²θ
sin²θ + cos²θ = 1
1 + cot²θ = cosec²θ
Sin(A + B) = SinACosB + CosASinB
Sin(A - B) = SinACosB - CosASinB
Cos(A + B) = CosACosB - SinASinB
Cos(A - B) = CosACosB + SinASinB
Tan(A + B) = TanA + TanB/1 - TanATanB
Tan (A - B) = TanA - TanB/1 + TanATanB
Sin2A = 2SinACosA
Cos2A = 1 - 2Sin²A or Cos2A = 2cos²A - 1
Tan2A = 2TanA/1 - Tan²A
Media attachments
logarithmic-function-graph.GIF (image/GIF)
trig.PNG (image/PNG)
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