Criado por Sam Simpson
mais de 7 anos atrás
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Questão | Responda |
WATER FORMULA | H20 |
AMMONIA FORMULA | NH3 |
CARBON DIOXIDE | CO2 |
CHLORINE | Cl2 |
HYDROGEN | H2 |
OXYGEN | O2 |
RELATIVE ATOMIC MASS (Ar) | Multiply each relative isotopic mass by its relative abundance then add up the results Then divide by the sum of the abundances |
Relative Formula Mass (Mr) | Find the relative atomic masses then add them all together to get the relative formula mass |
Empirical Formula | Empirical Formula of glucose C6H12O6 numbers in molecular formula are 6 : 12 : 6 simplify the ratio by the biggest number that goes into 6 12 6 so 6 divide all three numbers by 6 and the empirical formula is CH2O |
Avagrados Constant (You will need to calculate number of particles) | 6.02x10 to the power of 23 |
Number of Particles | Example: Oxygen How many atoms are there in five moles of oxygen? Oxygen has 2 atoms it is O2 Avogrados Constant multiplied by number of moles 6.02x10 to the power of 23 multiplied by 5 = 3.01 x 10 to the power of 24 there are 2 atoms in oxygen so multiply it by 3.01 x 10 to the power of 24. so the answer is 6.02 x 10 to the power of 24 |
Concentration = | Mass of Solute --------------------- Volume of Solution |
Rr | Distance Travelled by Solute ---------------------------------------- Distance travelled by solvent |
Equation for Neutralisation | Acid + Base ---> Salt + Water |
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