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2000706
THE MOLE
Descrição
Helps for calculations on "the mole" and any extra info!
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chemistry
science
international gcse
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rosie_femm
, atualizado more than 1 year ago
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rosie_femm
mais de 9 anos atrás
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Resumo de Recurso
THE MOLE
Moles of a mass
Moles = Mass/Mr
E.G 2.4 Magnesium= 2.4/24= 0.1 moles
1 Mole of any substance contains the same number of particles, this number is 6.0x10(23)
This is Avogadro's number
Mass= Moles x Mr
Moles of a Solution
Moles = concentration/Volume
Units of concentration = mol/dm(3)
Unit of volume = dm(3)
E.G 25cm(3) of 0.100 mol/dm(3) of Sodium solution = (0.100 x 25) / 1000 = 2.5x10(-3)
Most experiments do not use 1dm(3) of solution, much smaller volumes are used, therefore you must convert cm(3) to dm(3)
1 dm(3) = 1000 cm(3)
To convert cm(3) to dm(3) divide by 1000
Or moles = (conc x vol)/1000
Moles of Gases
Moles = Volume (dm3) / 24 (dm3)
OR Moles = volume (cm3) / 24,000 (cm3)
One mole of any gas at room temp and pressure has the volume of 24(dm3)
Yield
The amount of a product obtained from a chemical reaction is known as the yield
Percentage yield is easier to talk about.
This compares the amount of product that the reaction really produces with the maximum amount that it could possibly be
% Yield = (amount of product actually made / Maximum amount of product possible) x 100
No atoms are lost or gained, it is not always possible to obtain the calculated amount of yield.
This is because:
The reactions may not be completely pure
The reaction may not go to completion because it is reversible
Some of the product may be left behind in the apparatus
Some of the product may be lost when it is separated from the reaction mixture of its other products
Some of the reactants may react in ways different to the expected reaction to give unexpected products.
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