Reaction with HCl - substitution reaction - HCl replaces -OH group, forming a haloalkane
Reaction with conc. H2SO4/heat - elimination reaction - OH group attached and a H atom are removed from the organic molecule. Double bond forms between two carbons creating an alkene
Shape of ethanol is bent like H2O around the O atom so it is soluble in water. However, the longer the C chain, the more non-polar it is, so it is less soluble in water
MPt and BPt - low because week intermolecular forces. As C chain increases, the strength of the intermolecular forces also increase so MPt and BPt increase
Combustion into H2O and CO2 - clean burning, hot, blue flame
Oxidation - two hydrogen's attached to the same carbon as the OH group are replaced by a double bond with Oxygen. A Carboxylic acid is formed. Needs acidic MnO4- or C2O72-
Elimination - OH group is removed and a double bond is formed - poor get poorer - both major and minor products - need conc. H2SO4
Substitution - OH group replaced by a Halogen. Need PCl3/PCl5/SOCl2. conc. HCl can be used with tertiary alcohols at room temp which are small and therefore soluble in water. The Haloalkane formed is insoluble and forms a cloudy layer above the aqueous solution

	Criado por Olivia McKenzie mais de 9 anos atrás

NCEA L2/3 Calculus and Chemistry (Chem - Structure and bonding) Slides sobre Organic Chemistry, criado por Olivia McKenzie em 26-07-2015.