The GCD of 360 and 48 is
24
18
28
(3×10³×3.6×(10²)^3)/(2.7×10⁻⁴)=
4×10¹⁰
4×10¹³
4×10¹⁶
If x=(a+b)² and y=(a-b)² then x-y=
2ab
3ab
4ab
If A=4√5-4 and B=5√5 then
A=B
A<B
A>B
Given the numbers: A=8/3+5÷(1-2/5) ; B=(55×10³×2¹⁰)/(10⁴×2⁹) ; C=(4+√5)(4-√5) ; D=2√45+√81-3√20+2 then A=B=C=D
Given: X=3√27+√48+√75 and Y=√12-2√48+√192. 1) Write X and Y in the form of a√b. 2) Compare X and Y. 3) Rationalize the denominator of: X/(Y+1) 4) Assume that the dimensions of the rectangle ABCD are U and V where U=√XY and V=X+Y. Calculate U and V, then evaluate the area of ABCD.
1) X=18√3 ; Y=2√3 2) X>Y 3) X/(Y+1)=(18√3(2√3-1))/11 4) U=√XY=6√3 ; V=20√3 Area=XY=360.
1) Y=18√3 ; X=2√3 2) X>Y 3) X/(Y+1)=(18√3(2√3-1))/11 4) U=√XY=3√3 ; V=2√3 Area=XY=12.
1) Rationalize the expression: √3/(3√2+√3) 2) Deduce that: √3/(3√2+√3)-(√6-11)/5 is an integer.
) √3/(3√2+√3)=(√6+1)/5 2) √3/(3√2+√3)-(√6-11)/5=12/5
1) √3/(3√2+√3)=(√6-1)/5 2) √3/(3√2+√3)-(√6-11)/5=2
