\(i^{2}\) =
1
-1
\(i\)
\(-i\)
\(-i^{2}\)=
\(\frac{5}{i}\)=
5
-5
\(5i\)
\(-5i\)
\( (1+i)^{2}\) =
\(2i\)
\(2+2i\)
\(-2+2i\)
2
\( (2+5i).(3-2i) \)=
\(-4+11i\)
\(16-19i\)
\(6-10i\)
\(16+11i\)
