Newton’s [blank_start]third[blank_end] law of motion explains how Jerod starts his skateboard moving. This law states that every [blank_start]action[blank_end] has an [blank_start]equal and opposite reaction[blank_end]. This means that forces always act in [blank_start]pairs[blank_end]. First an [blank_start]action[blank_end] occurs—Jerod pushes against the ground with his foot. Then a [blank_start]reaction[blank_end] occurs—Jerod moves forward on his skateboard. The reaction is always [blank_start]equal[blank_end] in [blank_start]strength[blank_end] to the action but in the [blank_start]opposite[blank_end] direction.
If Jerod pushes against the ground with greater force, how will this affect his forward motion? Use Newton's 3rd Law!!!!!!
Responda
His action force will be smaller, so the reaction force will be even greater as well. Jerod will be pushed forward with less force, and this will make him go faster and farther.
His action force will be greater, so the reaction force will be smaller as well. Jerod will be pushed forward with less force, and this will make him go faster and farther.
His action force will be greater, so the reaction force will be greater as well. Jerod will be pushed forward with more force, and this will make him go faster and farther.
Questão 3
Questão
Equal and Opposite Forces
The forces involved in actions and reactions can be represented with [blank_start]arrows[blank_end]. The way an arrow points shows the [blank_start]direction[blank_end] of the force, and the size of the arrow represents the [blank_start]strength[blank_end] of the force. Look at the skateboarders in the Figure below. In the top row, the arrows represent the [blank_start]forces[blank_end] with which the skateboarders push against each other. This is the [blank_start]action[blank_end]. In the bottom row, the arrows represent the forces with which the skateboarders move [blank_start]apart[blank_end]. This is the [blank_start]reaction[blank_end]. Compare the top and bottom arrows. They point in different [blank_start]directions[blank_end], but they are the same [blank_start]size[blank_end]. This shows that the [blank_start]reaction[blank_end] forces are [blank_start]equal[blank_end] and [blank_start]opposite[blank_end] to the [blank_start]action[blank_end] forces.