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NBT Toets 3

Rika Grobler 20 questions

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Questions in this quiz (20)

  1. 1Bepaal die waarde van \(2^{1001} - 2^{1000} -2(2^{999}) \)

    Determine the value of \(2^{1001} - 2^{1000} -2(2^{999}) \)
    1. A0
    2. B2
    3. C\(3(2^{2001}) \)
    4. D\(2^{1002}\)
  2. 2Bepaal die waarde van n waarvoor/ Determine the value for which \(4(9^n)-9^n=3^{801}\)

    1. A802
    2. B400
    3. C199
    4. D798
  3. 3Vir watter waarde(s) van \(c\) sal \(y=3x+c\) 'n raaklyn aan \(y=x^2 -x-3\) wees?
    For which vaue(s) of \(c\) will \(y=3x+c\) be a tangent to \(y=x^2 -x-3\) ?
    1. A-3
    2. B3
    3. C7
    4. D-7
  4. 4Vir watter waarde(s) van \(x\) sal \(\frac{x^2+1}{(x-5)(x+8)}=0\)

    For which values of \(x\) will \(\frac{x^2+1}{(x-5)(x+8)}=0\)
    1. A\(\pm1\)
    2. B5 of/ or -8
    3. C1
    4. Dgeen reële waardes/ no real values
  5. 5Vereenvoudig/ Simplify: \(3^{n+4001}+3^{n+4001}+3^{n+4001}=\)
    1. A\(3^{n+12003}\)
    2. B\(9^{n+4001}\)
    3. C\(3^{n+4002}\)
    4. D\(3^{3n+4001}\)
  6. 6Een van die oplossings van \(y-x+5=0\) en \(y+x^2=1\) is

    One of the solutions of \(y-x+5=0\) and\(y+x^2=1\) is
    1. A(2; -3)
    2. B(-2; 3)
    3. C(3; -2)
    4. D(-3; 2}
  7. 7Bepaal die volgende term van die ry 4; 6; 12; 30; 84.....
    Determine the following term in the sequence 4; 6; 12; 30; 84.....
    1. A336
    2. B420
    3. C168
    4. D246
  8. 8Pinochio se neus is 3 cm lank. Elke keer wat hy 'n leuen vertel, word dit met \(\frac{2}{3}\) van die vorige lengte langer.Bepaal wat die langste is wat sy neus ooit kan word in cm.

    Pinochio's nose is 3 cm long. Every time he tells a lie, it becomes longer with \(\frac{2}{3}\) of the previous length . Determine what is the longest that his nose can ever be in cm.
    1. A6
    2. B7
    3. C8
    4. D9
  9. 9Bepaal die aard van die wortels van/ Determine the nature of the roots of \(x^2-2x+7=0\)
    1. AGelyk/ Equal
    2. BRasianaal en ongelyk/ Rational and unequal
    3. CIrrasionaal/ Irrational
    4. DNie-reëel/ Non real
  10. 10Watter formule kan gebruik word om te bepaal hoeveel geld per jaar belê moet word teen 12% p.j. maandeliks saamgestel as daar na 4 jaar R9000 beskikbaar moet wees.

    Which formula can be used to determine how much money should be invested per year at 12% pa. compounded monthly if R9000 must be available after 4 years.
    1. A\(\frac{9000}{((1+0,12)^4}\)
    2. B\(\frac{9000}{(1+0,12)^{48}}\)
    3. C\(\frac{9000}{(1+0,01)^4}\)
    4. D\(\frac{9000}{(1+0,01)^{48}}\)

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Hierdie toets dek meestal graad 11 wiskunde
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