Kc | Karteikarten

Frage	Antworten
Homogenous equilibria	All eq. species are gases
Hetergenous eq.	Different states Only (Aq) and (g) included in Kc expression
RICE	Reacting amounts Initial mole Change in mole Equilibrium
Calculations for Kc from RICE	[NO2] = eq. mole / total vol.
Mole fraction	Ratio of v to total gas v of that gas
Fromula	Mole1/2(A) = nA/total n
Sum of n always equal:	1
Partial pressure	Pressure of that gas in a mixture
Formula of PP	P(A) = (n1/2 * total P)
Sum of PP =	Total P
Kp expression	Kp = p(C)/p(A)p(B)
Why does Kp only include gases?	As only gases have pp
Calculating Kp (3)	1. find n1/2 2. Calculate pp 3. Express pp
Effect of T on equilibrium constant K EXO REACTIONS	^T = K decrease = decrease eq. yield of product
Effect of ^ T on Kp for EXO	^ T = Decrease Kp p(x)/(py) ratio now > Kp Kp doesn't = p(x)/p(y) Eq. shifts to LHS to ^ R so ratio now = Kp
Effect of ^P on Kp	position of eq. shifts Kp REMAINS THE SAME

Kc

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