3481778
Description
Quiz by Zeinab Zeineddine, updated more than 1 year ago
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Created by Zeinab Zeineddine
about 9 years ago
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Question 1
Question
The GCD of 360 and 48 is
Answer
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24
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18
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28
Question 2
Question
(3×10³×3.6×(10²)^3)/(2.7×10⁻⁴)=
Answer
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4×10¹⁰
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4×10¹³
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4×10¹⁶
Question 3
Question
If x=(a+b)² and y=(a-b)² then x-y=
Answer
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2ab
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3ab
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4ab
Question 4
Question
If A=4√5-4 and B=5√5 then
Answer
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A=B
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A<B
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A>B
Question 5
Question
Given the numbers:
A=8/3+5÷(1-2/5) ; B=(55×10³×2¹⁰)/(10⁴×2⁹) ; C=(4+√5)(4-√5) ; D=2√45+√81-3√20+2
then A=B=C=D
Answer
- True
- False
Question 6
Question
Given: X=3√27+√48+√75 and Y=√12-2√48+√192.
1) Write X and Y in the form of a√b.
2) Compare X and Y.
3) Rationalize the denominator of: X/(Y+1)
4) Assume that the dimensions of the rectangle ABCD are U and V where U=√XY and V=X+Y.
Calculate U and V, then evaluate the area of ABCD.
Answer
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1) X=18√3 ; Y=2√3 2) X>Y 3) X/(Y+1)=(18√3(2√3-1))/11 4) U=√XY=6√3 ; V=20√3 Area=XY=360.
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1) Y=18√3 ; X=2√3 2) X>Y 3) X/(Y+1)=(18√3(2√3-1))/11 4) U=√XY=3√3 ; V=2√3 Area=XY=12.
Question 7
Question
1) Rationalize the expression: √3/(3√2+√3)
2) Deduce that: √3/(3√2+√3)-(√6-11)/5 is an integer.
Answer
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) √3/(3√2+√3)=(√6+1)/5 2) √3/(3√2+√3)-(√6-11)/5=12/5
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1) √3/(3√2+√3)=(√6-1)/5 2) √3/(3√2+√3)-(√6-11)/5=2
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