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957561
DERIVADAS CON FÓRMULA
Description
Quiz on DERIVADAS CON FÓRMULA, created by GUADALUPE CASTRO on 31/05/2014.
Quiz by
GUADALUPE CASTRO
, updated more than 1 year ago
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Created by
GUADALUPE CASTRO
about 10 years ago
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Resource summary
Question 1
Question
La derivada de la función \(x^4+5x^5-4x+2\)es
Answer
\(-4+4 x^3+25 x^4\)
\(-4+4 x+25 x\)
\(-4+ x^3+x^4\)
Question 2
Question
La derivada de la función \(\sqrt{x}+\sqrt[4]{x}-\sqrt[5]{x^3}\) es:
Answer
\(\frac{1}{4 x^{1/4}}+\frac{1}{5 \sqrt{x}}-\frac{3 x^3}{6 \left(x^3\right)^{4/5}}\)
\(\frac{1}{4 x^{3/4}}+\frac{1}{2 \sqrt{x}}-\frac{3 x^2}{5 \left(x^3\right)^{4/5}}\)
\(\frac{1}{4 x^{3/4}}+\frac{1}{2 \sqrt{x}}-\frac{3 x^4}{-7 \left(x^6\right)^{3/2}}\)
Question 3
Question
La derivada de la función \(\left(x^2+3x\right)\text{Sin}[x]\) es:
Answer
\(\left(3 x+x^2\right)\text{Sin}[x] +(3+2 x) \text{Cos}[x]\)
\((2 x+3) \text{Cos}[x]\)
\(\left(3 x+x^2\right) \text{Cos}[x]+(3+2 x) \text{Sin}[x]\)
Question 4
Question
La derivada de la función \(\frac{e^x+1}{x}\) es:
Answer
\(\frac{-1-e^x+e^x x}{x^2}\)
\(\frac{e^x}{1}\)
\(\frac{\left(e^x+1\right)+(x)e^x}{x^2}\)
Question 5
Question
La derivada de la función \(5\text{ArcSin}\left[x^4\right]\) es
Answer
\(\frac{20 x^3}{\sqrt{1-x^8}}\)
\(\frac{x^4}{\sqrt{1-x^2}}\)
\(\frac{3x^4}{\sqrt{x^4-1}}\)
Question 6
Question
La derivada de la función\((x \text{Cos}[x])^3\) es:
Answer
\(3 (-x \text{Sin}[x]+\text{Cos}[x])^2\)
\(3 (x \text{Cos}[x])^2 (-x \text{Sin}[x]+\text{Cos}[x])\)
\(3 (x \text{Cos}[x])^2\)
Question 7
Question
La derivada de la función \(\text{Ln}(\text{ArcSin} x)\) es:
Answer
\(\frac{1}{\text{ArcSin} x \sqrt{1-x^2} }\)
\(\frac{1}{\text{ArcSin} x\text{ }}\)
\(\frac{1}{x }.\frac{1}{\sqrt{1-x^2}}\)
Question 8
Question
La derivada de la función \(\text{ArcSec}\left[10^x\right]\)
Answer
\(\frac{10^x \text{Ln}[10]}{x\sqrt{x^2-1}}\)
\(\frac{10^x }{10^x\sqrt{\left(10^{ x}\right)^2-1}}\)
\(\frac{10^x \text{Ln}[10]}{10^x\sqrt{\left(10^{ x}\right)^2-1}}\)
Question 9
Question
La derivada de la función \(\text{Cos}[4x]+\text{Sin}\left[3x^3\right]-\text{Sec}\left[e^x\right]\) es:
Answer
\(\text{Cos}\left[3 x^3\right]-\text{Sin}[4 x]-\text{Sec}\left[e^x\right] \text{Tan}\left[e^x\right]\)
\(\text{Cos}\left[9 x^2 \right]- \text{Sin}[4]-\text{Sec}\left[e^x\right] \text{Tan}\left[e^x\right]\)
\(9 x^2 \text{Cos}\left[3 x^3\right]-4 \text{Sin}[4 x]-e^x \text{Sec}\left[e^x\right] \text{Tan}\left[e^x\right]\)
Question 10
Question
La derivada de la función \(\text{Cot}\left[e^{x^2+x}\right]\) es:
Answer
\(-\text{Csc}^2\left[e^{x+x^2}\right]e^{x+x^2} (1+2 x) \)
\(-\text{Csc}^2\left[e^{x+x^2}\right]\)
\(-\text{Csc}^2\left[e^{x+x^2} (1+2 x)\right] \)
Question 11
Question
La derivada de la función \(\sqrt[5]{(3x+5\text{Cos}[x])^6}\) es:
Answer
\(\frac{6}{5} (3 x+5 \text{Cos}[x])^{\frac{1}{5}} (3-5 \text{Sin}[x])\)
\(\frac{6}{5} (3 x+5 \text{Cos}[x])^{\frac{1}{5}}\)
\(\frac{6}{5} (3-5 \text{Sin}[x])^{\frac{1}{5}}\)
Question 12
Question
Las formulas que se utilizan para derivar la función \(y=\frac{e^x\text{Lnx}}{\text{Cos}[x]}\)son:
Answer
\(d[u v]=u \text{v$\acute{ }$}+ v \text{u$\acute{ }$}\)
\(d\left[\frac{u}{v}\right]=\frac{v \text{u$\acute{ }$}- u \text{v$\acute{ }$}}{v^2}\)
\(d[u \pm v]=\text{u$\acute{ }$}\pm \text{v$\acute{ }$}\)
\(d[u(v)]=\text{u$\acute{ }$}(v) \text{v$\acute{ }$}\)
\(d[k u]=k \text{u$\acute{ }$}\)
Question 13
Question
Las fórmulas que se utilizan para derivar la función \(y=\frac{\text{Tan}(\text{Arc} \text{Cos} x)}{x^2}\) son:
Answer
\(d[u v]=u \text{v$\acute{ }$}+ v \text{u$\acute{ }$}\)
\(d\left[\frac{u}{v}\right]=\frac{v \text{u$\acute{ }$}- u \text{v$\acute{ }$}}{v^2}\)
\(d[u \pm v]=\text{u$\acute{ }$}\pm \text{v$\acute{ }$}\)
\(d[u(v)]=\text{u$\acute{ }$}(v) \text{v$\acute{ }$}\)
\(d[k u]=k \text{u$\acute{ }$}\)
Question 14
Question
Las fórmulas que se utilizan para derivar la función \(y=\text{Sen}(\text{Lnx}+\text{ArcSecx})\) son:
Answer
\(d[u v]=u \text{v$\acute{ }$}+ v \text{u$\acute{ }$}\)
\(d\left[\frac{u}{v}\right]=\frac{v \text{u$\acute{ }$}- u \text{v$\acute{ }$}}{v^2}\)
\(d[u \pm v]=\text{u$\acute{ }$}\pm \text{v$\acute{ }$}\)
\(d[u(v)]=\text{u$\acute{ }$}(v) \text{v$\acute{ }$}\)
\(d[k u]=k \text{u$\acute{ }$}\)
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