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6356499
Allgemeine und molekulare Genetik 2
Descripción
Bachelor Mikrobiologie Test sobre Allgemeine und molekulare Genetik 2, creado por Anna Ullrich el 15/09/2016.
Sin etiquetas
mikrobiologie
bachelor
Test por
Anna Ullrich
, actualizado hace más de 1 año
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Creado por
Anna Ullrich
hace alrededor de 8 años
17
1
0
Resumen del Recurso
Pregunta 1
Pregunta
What's right: Synthetic lethality ...
Respuesta
Combinatorial effects between alleles or substances
Effects in synthetic biology
An effect specific to a double mutation (not seen in the singles)
An effect specific to a mutation in combination with a SMI-small molecule inhibitor (not seen by either mutation or SMI alone)
Pregunta 2
Pregunta
What's right: Phage lambda lysogen ...
Respuesta
C1 represses lambda's lysogenic genes, c2 activates int- and c1 transcription, c3 stabilizes c2
C1 represses lambda's lysogenic genes, c2 represses int- and c1 transcription, c3 destabilizes c2
C1 represses lambda's lytic genes, c2 activates int- and c1 transcription, c3 stabilizes c2
C1 represses lambda's lytic genes, c2 represses int- and c1 transcription, c3 destabilizes c2
Pregunta 3
Pregunta
What's right: Bacterial transformation
Respuesta
The mechanism of gram+ and gram- DNA uptake is not related
Gram- bacteria possess an outer membrane requiring an additional pore for DNA uptake
Gram+ bacteria possess an outer membrane requiring an additional pore for DNA uptake
Gram+ and gram- bacteria have a pilus structure, a dsDNA receptor and an inner membrane pore in common
Pregunta 4
Pregunta
What's right: Intra- vs extragenic complementation
Respuesta
Genetic complementation between mutations in different genes does not require wild type alleles
Extragenic complementation is rare and requires mutations in different functional domains
Intragenic complementation is rare and depends on the presence of domains that function independently
Molecular complementation depends on addition of the wild gene
Pregunta 5
Pregunta
What's right: Dominant vs epistatic
Respuesta
a is epistatic to locus b , if the double mutant (a,a/b,b) has the same phenotype as the single mutant (a,a)
a is epistatic to b, means: Pht(a,b)=Pht(a,B) .. (although Pht(A,b)≠Pht(A,B))
dominant : Pht(A,A)=Pht(a,A)
dominant relates alleles of 1 gene, epistatic relates an allele to another gene
A is dominant over a: Pht(a,A) = Pht(a,a)
Pregunta 6
Pregunta
What's right: gene vs allele
Respuesta
a ncRNA is not encoded by a gene, because it is not translated
a centromere is not a gene, because it is not transcribed
a bacterial cistron is not a gene, because it contains several functional units
a gene is a functional unit in the genome, activated by transcription while an allele is a sequence variant of a gene
a bacterial operon is not a gene, because it contains several functional units
Pregunta 7
Pregunta
What's right: Falsifyability
Respuesta
According to Popper’s critical rationalism (P.c.r), a Sc.Hyp can’t be claimed true, without evidence
According to P.c.r. a single experiment, if well performed, can prove a hypothesis forever
According to P.c.r. a single experiment, if well performed, can disprove a hypothesis forever
According to P.c.r. a scientific hypothesis must make a prediction, which can be proven wrong
Pregunta 8
Pregunta
What's right: Suppressor mutation
Respuesta
A suppressor mutation blocks the expression of another gene
A suppressor mutation can’t occur in the same gene
A suppressor mutation must occur in tRNA
A suppressor blocks the appearance of a mutant phenotype
Pregunta 9
Pregunta
What's right: What is the phenotype?
Respuesta
Many genes do not cause a phenotype
The phenotype of a given mutation must be detectable under all conditions
The phenotype of a mutation can change according to the situation
The phenotype ist the observable impact of an allele
Pregunta 10
Pregunta
Connect the topic with the correct boxes/key words ... BACTERIAL RECOMBINEERING
Respuesta
attB/P/L/R
targetted DSB
RE enzyme free assembly of bacterial, genome-size DNA
Efficient, RE enzyme free transfer of inserts between plasmids
Inhibition of RecBCD
RE enzyme free sub cloning from large inserts
RE enzyme free correction of genetic defects in vivo
Bacterial immune system
Exo, Beta, Gam
Edition through DSB-repair
Pregunta 11
Pregunta
Connect the topic with the correct boxes/key words ... GATEWAY TECHNOLOGY
Respuesta
attB/P/L/R
targetted DSB
RE enzyme free assembly of bacterial, genome-sized DNA
Efficient, RE enzyme free transfer of inserts between plasmids
RE enzyme free sub cloning from large inserts
RE enzyme free correction of genetic defects in vivo
Bacterial immune system
Exo, Beta, Gam
Editing through DSB-repair
Cloning from donor to recipient
Pregunta 12
Pregunta
Connect the topic with the correct boxes/key words ... CRISPR
Respuesta
attB/P/L/R
targetted DSB
RE enzyme free assembly of bacterial, genome-size DNA
Efficient, RE enzyme free transfer of inserts between plasmids
Inhibition of RecBCD
RE enzyme free subcloning from large inserts
RE enzyme free correction of genetic defects in vivo
Bacterial immune system
Exo, Beta, Gam
Editing through DSB-repair
Pregunta 13
Pregunta
Connect the topic with the correct boxes/key words ... YEAST RECOMBINEERING
Respuesta
attB/P/L/R
targetted DSB
RE enzyme free assembly of bacterial, genome-size DNA
Efficient, RE enzyme free transfer of inserts between plasmids
Inhibition of RecBCD
RE enzyme free subcloning from large inserts
RE enzyme free correction of genetic defects in vivo
Bacterial immune system
Exo, Beta, Gam
Editing through DSB-repair
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