All Hydrocarbons
Molecular compounds
Apart of a Homologous series - same General formula and functional group (site where reactions occur)
Saturated hydrocarbons - all atoms linked by single covalent bonds
Molecular - weak intermolecular forces
MPt + BPt - increase with length of carbon chain. As molar mass increases, more electrons attracted to the neighbouring nuclei of molecules, so Van der Waals forces are stronger and there is more energy required to break them
Solubility - all insoluble. Non-polar because C-H are non-polar
Soluble in cyclohexane
Pie de foto: : Substitution - needs UV light - Bromine solution decolourises
Pie de foto: : Complete combustion
Diapositiva 4
Alkenes - CnH2n - ene
Unsaturated hydrocarbons - contain double C bonds
CnH2n
Addition reaction - double bond breaks, molecule splits and adds to each side of double bond
Hydrogenation reaction - Double bond breaks, an H added to each side of double bond. Ni = catalyst
Hydration reaction - Double bond breaks, H atom and OH atom added. H+ = catalyst
Oxidation reaction - Double bond breaks, two OH groups are added to either side (needs acidic solution to produce also a changed ion (eg Mn2+). Neutral solution, compound is formed (eg MnO2)
Test for unsaturation
Add Br2 (aq) and shake
Br2 water de-colourises rapidly, from orange to colourless, when it reacts with an alkene (eg. cyclohexene or an alkyne)
The alkene is insoluble and forms a layer on top of the Br2
Test for saturation
Add Br2 (aq) and shake
Br2 water de-colourised slowly, from orange to colourless, with UV light when it reacts with an alkane
The alkane is insoluble and forms a layer on top of the Br2
Diapositiva 7
Alkynes - CnH2n-2
Unsaturated hydrocarbon - contain triple C bonds
Diapositiva 8
Conditions required for reactions
With Bromine water - UV LIGHT PCl2, NH3 - No conditions required
KOH (alcholic) needed for elimination of haloakanes
Diapositiva 9
Substitution
An atom of group of atoms is replaced by another atom or group of atoms
Diapositiva 10
Separation in layers
Non-polar/Polar separatione.g. Bromine water is polar and therefore non-polar organic reactant and product will not dissolve in water (bromohexane) - two layers form as this polar and non-polar layer, do not mix
Diapositiva 11
Cis-Trans Isomerism
Carbon - carbon double bond must be present - prevents any rotation about this bond
Therefore, atoms of groups of atoms attached to the carbon are fixed in position
C atoms at both ends of the double bond must have two different groups (or atoms) attached
Cannot have two of the same atoms or groups of atoms attached to one of the carbons
Diapositiva 12
Carboxylic acids - CnH2n+1COOH _oic acid
Reaction with sodium carbonate - acid/base reaction (-oic acid donates a proton, forming -oate ion) - sodium -oate, water and carbon dioxide are formed
Weak acids - PH>3
Higher MPts and BPts than Alcohols of similar C chain length because there are two sets of intermolecular forces per molecule. More energy is required to break those bonds compared to alcohols of same length
Solubility - yes but as C chain increases, solubility decreases
Acid + Metal = Metal salt + H2
Acid + Metal Carbonate = Metal salt + CO2 + H2O
Acid + Base = Metal salt + Water
Diapositiva 13
Amines (aminoalkanes)
Base. Weaker than NH3
NH2 group attached
Turns litmus blue in water as produce OH ions
Reaction with HCl or H2SO4 - acid/base reaction (Amines accept protons from acids due to being basic) - sulfuric acid and hydrochloric acid donate protons to the amine to form organic salts
MPt and BPt - as the length of the molecule increases so does the MPt and BPt of the amines. As the molar mass of the amine increases so do the intermolecular forces
Solubility - Amines with a small number of carbons are very soluble. As the length of the C chain increases, amines become less soluble
Can form complex ions with copper [Cu(CH3CH2NH2)4]2+
Diapositiva 14
Alcohol - _ol - CnH2n+1OH
Reaction with HCl - substitution reaction - HCl replaces -OH group, forming a haloalkane
Reaction with conc. H2SO4/heat - elimination reaction - OH group attached and a H atom are removed from the organic molecule. Double bond forms between two carbons creating an alkene
Shape of ethanol is bent like H2O around the O atom so it is soluble in water. However, the longer the C chain, the more non-polar it is, so it is less soluble in water
MPt and BPt - low because week intermolecular forces. As C chain increases, the strength of the intermolecular forces also increase so MPt and BPt increase
Combustion into H2O and CO2 - clean burning, hot, blue flame
Oxidation - two hydrogen's attached to the same carbon as the OH group are replaced by a double bond with Oxygen. A Carboxylic acid is formed. Needs acidic MnO4- or C2O72-
Elimination - OH group is removed and a double bond is formed - poor get poorer - both major and minor products - need conc. H2SO4
Substitution - OH group replaced by a Halogen. Need PCl3/PCl5/SOCl2. conc. HCl can be used with tertiary alcohols at room temp which are small and therefore soluble in water. The Haloalkane formed is insoluble and forms a cloudy layer above the aqueous solution
Diapositiva 15
Markovnikov's rule
"The rich get richer" - Hydrogen adds onto carbon attached to the most Hydrogen's
"The poor get poorer" - Hydrogen atom is eliminated from the carbon with the least amount of Hydrogen's attached to it
The major product (high-yeild) is one that follows rule. Minor product is the alternative
Diapositiva 16
Polymerisation - poly-
An addition reaction - the formation of a long chain molecule by a larger number of alkene molecules adding together at their double bonds. If the starting alkene, the monomer is ethene, the polymer formed is polythene
Diapositiva 17
Ways to test substances
Water - if soluble or insoluble
Litmus - red turned blue - basic, red stays red - acidic
Bromine water - soluble/insoluble, colour change (de colourisation of orange ion)
Diapositiva 18
Cycloalkanes - CnH2n - cyclo-_ane
Diapositiva 19
Haloalkanes
Substitution reaction - Haloalkane is substituted in for the anion of the other reactant
Elimination reaction - Haloalkane is eliminated and replaced with a double bond. Elimination is favoured when the solvent used is less polar than water. Use KOH (alcoholic). Produces major and minor products - the poor get poorer