Creado por Abhai Kollara
hace alrededor de 11 años
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Pregunta | Respuesta |
Sub : \(x^2\) + \(a^2\) | a \(\tan\) \(\theta\) |
Sub : \[\sqrt{x^2 - a^2}\] | a \(\sec\) \(\theta\) |
Sub : \[\sqrt{a^2 - x^2}\] | a \(\sin\) \(\theta\) or a \(\cos\) \(\theta\) |
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math.JPG (image/JPG)
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math.JPG (image/JPG)
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math.JPG (image/JPG)
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Image:
math1.JPG (image/JPG)
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Image:
math.JPG (image/JPG)
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Image:
math1.JPG (image/JPG)
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Image:
math.JPG (image/JPG)
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Image:
math1.JPG (image/JPG)
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Image:
math.JPG (image/JPG)
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Image:
math1.JPG (image/JPG)
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Image:
math.JPG (image/JPG)
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Image:
math1.JPG (image/JPG)
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Image:
math.JPG (image/JPG)
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Image:
math1.JPG (image/JPG)
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