New GCSE Maths required formulae

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Required formulae for the new maths GCSE - these will NOT be given during the exam, they must be learned in advance
Louise C
Flashcards by Louise C, updated more than 1 year ago More Less
Sarah Egan
Created by Sarah Egan over 8 years ago
Louise C
Copied by Louise C over 8 years ago
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Question Answer
Quadratic Formula - solve: \(a\)\(x^2\)+\(b\)\(x\)+\(c\)=\(0\) where \(a\) \(\neq\) \(0\) \begin{array}{*{20}c} {x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}\\ \end{array}
Circumference of a Circle: \(2\)\(\pi\)\(r\) or \(\pi\)\(d\) where \(r\)=radius, \(d\)=diameter
Area of a Circle: \(\pi\)\(r\)\(^2\)
Pythagoras theorem In any right-angled triangle where \(a\), \(b\) and \(c\) are the length of the sides and \(c\) is the hypotenuse: \(a^2\)+\(b^2\)=\(c^2\)
Trig: In any right-angled triangle \(ABC\) where \(a\), \(b\) and \(c\) are the length of the sides and \(c\) is the hypotenuse: \(sinA\)= \(sinA\)=\(\frac{a}{c}\)
Trig: In any right-angled triangle \(ABC\) where \(a\), \(b\) and \(c\) are the length of the sides and \(c\) is the hypotenuse: \(cosA\)= \(cosA\)=\(\frac{b}{c}\)
Trig: In any right-angled triangle \(ABC\) where \(a\), \(b\) and \(c\) are the length of the sides and \(c\) is the hypotenuse: \(tanA\)= \(tanA\)=\(\frac{a}{b}\)
Sine Rule: \(\frac{a}{sinA}\)=\(\frac{b}{sinB}\)=\(\frac{c}{sinC}\)
Cosine Rule: \(a^2\)= \(b^2\)+\(c^2\)-\(2\)\(b\)\(c\) \(cosA\)
Trigonometry: Area of a Triangle \(\frac{1}{2}\)\(a\)\(b\)\(SinC\)
Area of a Trapezium= (Where \(a\) and \(b\) are the lengths of the parallel sides and \(h\) is their perpendicular separation) \(\frac{1}{2}\) (\(a\) + \(b\))\(h\)
Volume of a Prism: area of cross section × length
Compound interest: Where \(P\) is the principal amount, \(r\) is the interest rate over a given period and \(n\) is number of times that the interest is compounded, Total accrued= Total accrued= \begin{array}\(P\left(1+ \frac{r}{100}\right)^n\end{array}
Where P(A) is the probability of outcome A and P(B) is the probability of outcome B: P(A or B) = P(A or B) = P(A) +P(B) - P(A and B)
Where P(A) is the probability of outcome A and P(B) is the probability of outcome B: P(A and B) P(A and B) = P(A given B) P(B)
Curved surface area of a cone: \(\pi\)\(r\)\(l\)
Surface area of a Sphere: \(4\)\(\pi\)\(r\)\(^2\)
Volume of a Sphere: \(\frac{4}{3}\)\(\pi\)\(r\)\(^3\)
Volume of a Cone: \(\frac{1}{3}\)\(\pi\)\(r\)\(^2\)\(h\)
Final Velocity \(v\): \(v\)=\(u\)+\(at\) (\(u\)=initial velocity, \(a\)=constant acceleration, \(t\)=time taken)
Displacement \(s\): \(s\)=\(ut\) +\(\frac{1}{2}\)\(a\)\(t\)\(^2\) (\(u\)=initial velocity, \(a\)=constant acceleration, \(t\)=time taken)
Velocity \(v\)\(^2\): \(v\)\(^2\)=\(u\)\(^2\)+ \(2\)\(as\) (\(u\)=initial velocity, \(a\)=constant acceleration, \(s\)=displacement)
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