Created by ricsalazar
over 8 years ago
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Question | Answer |
Base angles of an isosceles triangle formed from the radii of a circle are equal. (Base <'s isos. Triangle, = radii) | |
The angle at the centre is twice the angle at the circumference on the same arc. (< at centre) | |
The angle in a semi-circle is a right angle. (< in semi-circle) | |
Angles on the same arc are equal. (<'s on same arc) | |
Opposite angles of a cyclic quadralateral add to 180 degrees. (Opp. <'s, cyclic quad) | |
The exterior angle of a cyclic quadralateral is equal to the interior opposite angle. (Ext. <, cyclic quad) | |
The angle where the radius meets the tangent is 90 degrees. (Tgt. Perpendicular Rad) | |
Tangents from a point to a circle are the same length. (Equal tgt) | |
The perpendicular from the centre to the chord bisects the chord. (Perpendicular from centre to chord) | |
The exterior angles of a polygon add to 360. (Ext. < sum of polygon) | |
The interior angles of a polygon: sum= 180(n-2), Where n is the number of sides. (Int. < sum of polygon) | |
Each angle in an equaliteral triangle is 60 degree. (< in equailat. Triangle) | |
The base angles of an isosceles triangle are equal. (Base <'s isos. Triangle) | |
Interior angles in a quadrilateral add up to 360. (< sum of quad.) | |
The exterior angle of a triangle equals the sum of the two interior opposite angles. (Ext < of triangle) |
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